在 vespa 中实现自定义搜索器

Question

我已经在 Vespa 中创建了基本搜索应用程序，并实现了 Searcher class。我已经使用我的应用程序一张一张地提供了以下这些文件。

{
    "fields": {
        "album": "Good",
        "artist": "Arijit",
        "title": "tum ho",
        "year": 2017,
        "duration": 300
    }
}
{
    "fields": {
        "album": "Good",
        "artist": "Atif",
        "title": "bewajah",
        "year": 2017,
        "duration": 300
    }
}
{
    "fields": {
        "album": "bad",
        "artist": "Neha",
        "title": "tere",
        "year": 2017,
        "duration": 400
    }
}

我的搜索器 class 如下：

public class ExampleSearcher extends Searcher {

    @Override
    public Result search(Query query, Execution execution) {

        retrun execution.search(query); 
    }
}

现在，当我使用 API 搜索时：

http://localhost:8080/search/?album=good OR http://localhost:8080/search/?=good

我得到了结果：

{
    "root": {
        "id": "toplevel",
        "relevance": 1,
        "fields": {
            "totalCount": 0
        }
    }
}

但我应该得到这个结果输出：

{
    "root": {
        "id": "toplevel",
        "relevance": 1,
        "fields": {
            "totalCount": 2
        },
        "children": [{
            "id": "good",
            "relevance": 1,
            "fields": {
                "album": "Good",
                "artist": "Arijit",
                "title": "tum ho",
                "year": 2017,
                "duration": 300
            }
        }, {
            "id": "good",
            "relevance": 1,
            "fields": {
                "album": "Good",
                "artist": "Atif",
                "title": "bewajah",
                "year": 2017,
                "duration": 300
            }
        }]
    }
}

我做错了什么或者我应该怎么做？

Answer 1

要实际搜索内容节点而不是像示例中那样模拟 Hello world 结果，您需要将链 'inherits=vespa' 添加到 [=13= 中的搜索链配置中].

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