如何检查鼠标是否在 ContextMenuStrip 或其项目中

Question

我在我的表单应用程序中使用 ContextMenuStrip 作为我的下拉菜单。确切地说，当我单击按钮时，ContextMenuStrip 显示在它的正下方。一切都很好，但我真的想在鼠标离开其区域后自动关闭 ContextMenuStrip。好的，所以我尝试使用 MouseLeave 事件。再一次，一切正常，但是当我将下拉项添加到 ContextMenuStrip 中的某些 ToolStripItem 时，mouseLeave 事件没有将这个新区域识别为 ContextMenuStrip 的一部分。这是我最新的尝试，但还没有完成。知道如何解决这个问题吗？

    private void ContextMenuStrip_MouseLeave(object sender, EventArgs e)
    {
        ContextMenuStrip cms = (sender is ContextMenuStrip) ? sender as ContextMenuStrip : null;

        if (cms != null)
        {
            //List<Rectangle> cmsFullArea = new List<Rectangle>();
            //cmsFullArea.Add(new Rectangle(cms.Bounds.Location, cms.Bounds.Size));

            bool itemIsPressed = false;
            for (int i = 0; i < cms.Items.Count; i++)
            {
                if (cms.Items[i].Pressed) { itemIsPressed = true; break; }
            }

            if (!itemIsPressed) { cms.Close(); }
        }
    }

当我离开 CMS 以下拉项目时，这工作正常，但当我离开它们时，它不起作用。当我离开他的任何区域时，我需要关闭整个 CMS。

Answer 1

添加一个区域变量，它将 ContextMenuStrip 加上 DropDownMenus。

private Region rgn = new Region();

初始化区域：

public Form1() {
    InitializeComponent();

    rgn.MakeEmpty();
}

当ContextMenuStrip打开更新区域时：

private void contextMenuStrip1_Opened( object sender, EventArgs e ) {
    rgn.Union( contextMenuStrip1.Bounds );
}

在离开事件中检查鼠标是否在该区域内：

private void contextMenuStrip1_MouseLeave( object sender, EventArgs e ) {
    Point pnt = Cursor.Position;

    if( rgn.IsVisible( pnt ) == false ) {
        rgn.MakeEmpty();

        contextMenuStrip1.Close();
    }
}

当您创建一个新的 ToolStripDropDownMenu 添加项目到例如 toolStripMenuItem0 时，添加这些事件处理程序：

//toolStripMenuItem0 is an item of your ContextMenuStrip
toolStripMenuItem0.DropDown.MouseLeave += DropDown_MouseLeave;
toolStripMenuItem0.DropDown.Opened += DropDown_Opened;
toolStripMenuItem0.DropDown.Closed += DropDown_Closed;

private void DropDown_Closed( object sender, ToolStripDropDownClosedEventArgs e ) {
    ToolStripDropDownMenu tsddm = (ToolStripDropDownMenu)sender;

    rgn.Exclude( tsddm.Bounds ); //remove rect from region
}

private void DropDown_Opened( object sender, EventArgs e ) {
    ToolStripDropDownMenu tsddm = (ToolStripDropDownMenu)sender;

    rgn.Union( tsddm.Bounds ); //add rect to region
}

private void DropDown_MouseLeave( object sender, EventArgs e ) {
    Point pnt = Cursor.Position;

    if( rgn.IsVisible( pnt ) == false ) {
        rgn.MakeEmpty();

        contextMenuStrip1.Close();
    }
}

对每个 DropDownMenu you create做同样的事情。

Answer 2

正如我在评论中承诺的那样，我想 post 解决此问题的另一种方法。

首先是事件句柄的MouseLeave方法。此方法对 ContextMenuStrip (CMS) 和 ToolStripDropDownMenu (TSDDM) 通用。

    private void ContextMenuStrip_MouseLeave(object sender, EventArgs e)
    {
        ContextMenuStrip cms = (sender is ContextMenuStrip) ? sender as ContextMenuStrip : null;

        //Recognize CMS or TSDDM, in this case we dont need anything else
        if (cms != null)
        {
            //Check, if mouse position is on any of CMS DropDownMenus. 
            //If false, close CMS. If true, we dont want to close it - CMS is actively in use
            if (!IsMouseOnDropDown(cms.Items)) { cms.Close(); }
        }
        else
        {
            ToolStripDropDownMenu ddm = (sender is ToolStripDropDownMenu) ? sender as ToolStripDropDownMenu : null;

            if (ddm != null)
            {
                //As above, check mouse position against items DropDownMenus
                if (IsMouseOnDropDown(ddm.Items)) { return; }

                //Declare our CMS
                cms = GetPrimaryOwner(ddm);

                //Get TSDDM owner
                //var is important here, because we dont know if it is CMS or another TSDDM!!!
                //Also TSDDM and CMS have the same properties for our purpose, so var is OK
                var owner = ddm.OwnerItem.Owner;

                Point pnt = Cursor.Position;

                //If owner doesn't contains mouse position, close whole CMS
                if (!owner.Bounds.Contains(pnt))
                {
                    cms.Close();
                }
                else
                {
                    //If does, we need to check if mouse position is exactly on parent item, 
                    //because its prevent to TSDDM unnecessary close/open 
                    //(explanation: Mouse leave TSDDM -> TSDDM close; 
                                  //Mouse is on parent item -> TSDDM open)
                    for (int i = 0; i < owner.Items.Count; i++)
                    {
                        //Define own rectangle, because item has its own bounds against the owner
                        //so we need to add up their X and Y to get the real one
                        int x = owner.Bounds.X + (owner.Items[i] as ToolStripMenuItem).Bounds.X;
                        int y = owner.Bounds.Y + (owner.Items[i] as ToolStripMenuItem).Bounds.Y;
                        Rectangle rect = new Rectangle(new Point(x, y), (pupik.Items[i] as ToolStripMenuItem).Bounds.Size);

                        //If its our DropDownMenu and mouse position is in there,
                        //we dont want to close ddm
                        if ((owner.Items[i] as ToolStripMenuItem).DropDown == ddm
                            && rect.Contains(pnt))
                        {
                            return;
                        }
                    }

                    ddm.Close();
                }
            }
        }
    }

上面可以看到IsMouseOnDropDown和GetPrimaryOwner方法，所以有代码：

    private static bool IsMouseOnDropDown(ToolStripItemCollection itemCollection)
    {
        Point pnt = Cursor.Position;

        //All what we do is check, if some of DropDownMenus from input collection is active (Visible) 
        //and if mouse position is in it
        for (int i = 0; i < itemCollection.Count; i++)
        {
            if ((itemCollection[i] as ToolStripMenuItem).DropDown.Visible
                && (itemCollection[i] as ToolStripMenuItem).DropDown.Bounds.Contains(pnt))
            {
                return true;
            }
        }

        return false;
    }

    private static ContextMenuStrip GetPrimaryOwner(ToolStripDropDownMenu dropDownMenu)
    {
        //All what we do is take owner by owner until we find our CMS,
        //which is the last one -> primary owner
        object cmsItems = dropDownMenu;

        while (!(cmsItems is ContextMenuStrip))
        {
            cmsItems = (cmsItems as ToolStripDropDownMenu).OwnerItem.Owner;
        }

        return cmsItems as ContextMenuStrip;
    }

我们需要做的最后一件事是处理每个 DropDownMenu 和 ContextmenuStrip 的 mouseLeave 事件

   this.ContextMenuStrip1.MouseLeave += new System.EventHandler(ContextMenuStrip_MouseLeave);
   this.StripMenuItem1.DropDown.MouseLeave += new System.EventHandler(ContextMenuStrip_MouseLeave);

对于这个例子，我觉得一切正常，所以如果您发现错误，请告诉我。这只是一个例子，所以我没有在那里写 Try/Catch..

如何检查鼠标是否在 ContextMenuStrip 或其项目中

How to check if mouse is in ContextMenuStrip or in its items

c#

mouse

mouseleave

contextmenustrip