如何使用项目符号显示为输出?
How to use bullet symbol to display as output?
我用的是copy bullet symbol,放在char symbol中。但问题是它用 such blue color in mobile. My Requirement is, it should be black arrow 显示项目符号。
这是我的代码:
Spannable spannable = SpanUtils.createNestingParagraphsSpannable(strings,
'▶', mFirstLineIndent); //but this is not working as expected output.
public static Spannable createNestingParagraphsSpannable(List<String> paragraphs,
char bulletSymbol, int indent) {
List<ImprovedPair<Integer, Integer>> indexes = new ArrayList<>();
StringBuilder builder = new StringBuilder();
int count = CollectionUtils.emptyIfNull(paragraphs).size();
for (int i = 0, last = count - 1; i < count; ++i) {
int start = builder.length();
if (i > 0) {
builder.append(bulletSymbol); //here I am using the bullet symbol
builder.append(" ");
}
builder.append(paragraphs.get(i));
if (i < last) {
builder.append("\n\n");
}
indexes.add(new ImprovedPair<>(start, builder.length()));
}
尝试用“\u2023”替换您的“▶”
这是您要查找的符号的 unicode。
通过将此 unicode 放入字符串或字符中,将在打印时插入符号
尝试使用项目符号符号的 unicode 而不是符号本身。
喜欢:-
char bulletSymbol='\u2023';
我用的是copy bullet symbol,放在char symbol中。但问题是它用 such blue color in mobile. My Requirement is, it should be black arrow 显示项目符号。
这是我的代码:
Spannable spannable = SpanUtils.createNestingParagraphsSpannable(strings,
'▶', mFirstLineIndent); //but this is not working as expected output.
public static Spannable createNestingParagraphsSpannable(List<String> paragraphs,
char bulletSymbol, int indent) {
List<ImprovedPair<Integer, Integer>> indexes = new ArrayList<>();
StringBuilder builder = new StringBuilder();
int count = CollectionUtils.emptyIfNull(paragraphs).size();
for (int i = 0, last = count - 1; i < count; ++i) {
int start = builder.length();
if (i > 0) {
builder.append(bulletSymbol); //here I am using the bullet symbol
builder.append(" ");
}
builder.append(paragraphs.get(i));
if (i < last) {
builder.append("\n\n");
}
indexes.add(new ImprovedPair<>(start, builder.length()));
}
尝试用“\u2023”替换您的“▶”
这是您要查找的符号的 unicode。 通过将此 unicode 放入字符串或字符中,将在打印时插入符号
尝试使用项目符号符号的 unicode 而不是符号本身。
喜欢:-
char bulletSymbol='\u2023';