Swift 中的协议是引用类型还是值类型?

Is a protocol either a reference or value type in Swift?

我问这个问题的原因是因为我正在阅读使用委托的教程。根据我从其他 tutorials/articles 在线阅读的内容,据我所知,该特定教程并未创建保留周期。我还使用仪器(内存泄漏和僵尸)对其进行了测试,以确保没有内存泄漏。

我想弄清楚 class 是否只是简单地符合协议,这会创建引用吗?

我不认为是这样,但我想确定一下。

这是创建委托成员的协议和class:

import Foundation
import CoreBluetooth

protocol TransferServiceScannerDelegateProtocol: NSObjectProtocol {
    func didStartScan()
    func didStopScan()
    func didTransferData(data: NSData?)
}

class TransferServiceScanner: NSObject, CBCentralManagerDelegate, CBPeripheralDelegate {
    var centralManager: CBCentralManager!
    var discoveredPeripheral: CBPeripheral?
    var data = NSMutableData()
    weak var delegate: TransferServiceScannerDelegateProtocol?

    init(delegate: TransferServiceScannerDelegateProtocol?) {
        super.init()
        centralManager = CBCentralManager(delegate: self, queue: nil)
        self.delegate = delegate
    }


    //start of cbCentralDelegate method
    func centralManagerDidUpdateState(_ central: CBCentralManager) {
        switch central.state {
        case .poweredOn:
            print("Central is powered on...")
            break
        case .poweredOff:
            print("Central is powered off...")
            break
        default:
            print("Central manager changed state \(central.state)")
            break
        }
    }
    //end of cbCentralDelegate method

}

这是一个符合协议的视图控制器,但也有一个 属性 上面提到的 class 类型。我还不确定为什么这个视图控制器符合协议,但我认为这不会增加引用计数:

import UIKit

class CentralViewController: UIViewController, TransferServiceScannerDelegateProtocol {
    @IBOutlet var heartImage: UIImageView!
    @IBOutlet var scanButton: CustomButton!
    @IBOutlet var textView: UITextView!
    var transferServiceScanner: TransferServiceScanner!

    // MARK: TransferServiceScannerDelegateProtocol methods
    func didStartScan() {
        //
    }

    func didStopScan() {
        //
    }

    func didTransferData(data: NSData?) {
        //
    }
    //end of TransferServiceScannerDelegateProtocol methods


    override func viewDidLoad() {
        super.viewDidLoad()
        transferServiceScanner = TransferServiceScanner.init(delegate: self)
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }


    /*
    // MARK: - Navigation

    // In a storyboard-based application, you will often want to do a little preparation before navigation
    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        // Get the new view controller using segue.destinationViewController.
        // Pass the selected object to the new view controller.
    }
    */

}

I don't think this should increase the reference count:

var transferServiceScanner: TransferServiceScanner 将引用计数增加到 1,因为如果没有声明为弱引用或其他引用,所有引用都是强引用。

将委托变量存储为 weak 确保强引用不会双向传递,因此 ARC 可以取消初始化它们。

I'm trying to figure out if a class were to simply conform to a protocol, does this create a reference?

A class 始终是引用类型,无论您是通过协议还是直接引用它。因此,在其后面分配一个带有引用类型(class)的协议不会复制 class-对象,但您宁愿给出对该对象的另一个引用并增加 ARC 查看的引用计数.

protocol TransferServiceScannerDelegateProtocol: NSObjectProtocol {

你确定只有 class 可以实现协议,这就是为什么你可以声明 weak var delegate: TransferServiceScannerDelegateProtocol,因为只有 classes 可以实现 NSObjectProtocolNSObject & co.

无需声明协议 class - 仅结构或 class 都可以实现协议。但只有当您将协议限制为 class-only 时,您才能像使用 class 一样使用协议,并使用 weak 之类的东西。