swift coreML：没有 "options" 参数的预测函数

Question

在swiftdocumentation中，MLModel有两个预测函数

func 预测（来自：MLFeatureProvider）-> MLFeatureProvider。根据给定的输入特征值预测输出特征值。
func 预测（来自：MLFeatureProvider，选项：MLPredictionOptions）-> MLFeatureProvider。根据给定的输入特征值预测输出特征值。

但是，在我自动生成的 MLModel class 中，没有生成带有选项参数的函数。以下代码是我自动生成的预测函数。

func prediction(input: coreML_1denses_80iters_k213_2Input) throws -> coreML_1denses_80iters_k213_2Output {
    let outFeatures = try model.prediction(from: input)
    let result = coreML_1denses_80iters_k213_2Output(output1: outFeatures.featureValue(for: "output1")!.multiArrayValue!, lstm_1_h_out: outFeatures.featureValue(for: "lstm_1_h_out")!.multiArrayValue!, lstm_1_c_out: outFeatures.featureValue(for: "lstm_1_c_out")!.multiArrayValue!)
    return result
}

func prediction(input1: MLMultiArray, input2: MLMultiArray, lstm_1_h_in: MLMultiArray?, lstm_1_c_in: MLMultiArray?) throws -> coreML_1denses_80iters_k213_2Output {
    let input_ = coreML_1denses_80iters_k213_2Input(input1: input1, input2: input2, lstm_1_h_in: lstm_1_h_in, lstm_1_c_in: lstm_1_c_in)
    return try self.prediction(input: input_)
}

注意：顺便说一句，我想找到带有 "options" 参数的预测函数的原因是这个错误消息：

[coreml] Cannot evaluate a sequence of length 600, which is longer than maximum of 400.

而且我找到了一个名为 "usesCPUOnly" 的 solution, which is adding a forceCPU Flag in prediction function. The option can be found in MLPredictionOptions。但是，我找不到放置选项的地方。

Answer 1

一种方法是在自动生成的 class（在不同的源文件中）的 extension 中添加您自己的预测方法。

Answer 2

感谢@Matthijs Hollemans。我找到了解决方案。只需编写我自己的扩展并像这样覆盖预测功能。

func prediction(input: model_1denses_50iters_k213Input) throws -> model_1denses_50iters_k213Output {
    let options = MLPredictionOptions()
    options.usesCPUOnly = true
    let outFeatures = try model.prediction(from: input, options:options)
    let result = model_1denses_50iters_k213Output(output1: outFeatures.featureValue(for: "output1")!.multiArrayValue!, lstm_85_h_out: outFeatures.featureValue(for: "lstm_85_h_out")!.multiArrayValue!, lstm_85_c_out: outFeatures.featureValue(for: "lstm_85_c_out")!.multiArrayValue!)
    return result
}

swift coreML：没有 "options" 参数的预测函数

swift coreML: prediction function without "options" parameter

swift

lstm

coreml