如何在 cakephp 3.6 中 select 来自一个 table 的所有记录和来自另一个 table 的一些记录

Question

SELECT 我的Table.*, otherTable.foo, otherTable.bar...

how can we write above query in cakephp ? I tried this but didn't work.

$data = $this->Articles->find()->select(['Articles.*','Categories.name'])->innerJoineWith('Categories');

它在 SELECT Fees.* ASFees__*.

附近给我错误

因此，我必须写文章的所有专栏 Table。

$data = $this->Articles->find()->select(['Articles.id','Articles.name','Articles.title','Articles.description','Categories.name'])->innerJoineWith('Categories');

cakephp有解决办法吗？请告诉我。谢谢。

Answer 1

你可以这样做：

$this->Articles->find('all')->contain(['Categories' => function($q) {
                    return $q->select('Categories.name');
                }])->select($this->Articles);

$this->Articles in select statement will fetch all the records from the Articles table and $q->select('Categories.name') will fetch only Category name from the associated Categories table.

参考：https://github.com/cakephp/cakephp/issues/7913

Answer 2

$data = $this->Articles->find()
        ->select($this->Articles)
        ->select(['Categories.name'])
        ->innerJoineWith('Categories');