PDO 准备语句返回 false
PDO prepared statement returning false
知道为什么会返回 false 吗?
用于调用函数的代码:
$product = new Product;
$allProducts = $product->getProducts(12);
我正在调用的函数:
public function getProducts($limit)
{
$values = array($limit);
$statement = $this->conn->prepare('SELECT * FROM sellify_items ORDER BY id DESC LIMIT ?');
$statement->execute($values);
$result = $statement->fetchAll();
if ($result) {
return $result;
}
return false;
}
编辑:更新函数
public function getProducts($limit)
{
$values = array(intval($limit));
$statement = $this->conn->prepare('SELECT * FROM sellify_items ORDER BY id DESC LIMIT ?');
$statement->bindValue(0, $limit, PDO::PARAM_INT);
$statement->execute($values);
$result = $statement->fetchAll();
if ($result) {
return $result;
}
return false;
}
试试这个(注意转换为 int):
$statement->bindValue(0, (int) $limit, PDO::PARAM_INT);
知道为什么会返回 false 吗?
用于调用函数的代码:
$product = new Product;
$allProducts = $product->getProducts(12);
我正在调用的函数:
public function getProducts($limit)
{
$values = array($limit);
$statement = $this->conn->prepare('SELECT * FROM sellify_items ORDER BY id DESC LIMIT ?');
$statement->execute($values);
$result = $statement->fetchAll();
if ($result) {
return $result;
}
return false;
}
编辑:更新函数
public function getProducts($limit)
{
$values = array(intval($limit));
$statement = $this->conn->prepare('SELECT * FROM sellify_items ORDER BY id DESC LIMIT ?');
$statement->bindValue(0, $limit, PDO::PARAM_INT);
$statement->execute($values);
$result = $statement->fetchAll();
if ($result) {
return $result;
}
return false;
}
试试这个(注意转换为 int):
$statement->bindValue(0, (int) $limit, PDO::PARAM_INT);