PyQt5：为什么我只能为 QTableWidget 单元格使用两种颜色？

Question

所以我试图根据 item.text() 为我的 QTableWidget QTableWidgetItems 着色。这是我的代码：

from PyQt5 import QtCore, QtGui, QtWidgets
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *

import sys

class Table(QTableWidget):

    def __init__(self, parent):
        super(Table, self).__init__(parent)
        self.setColumnCount(9)
        self.setRowCount(1)
        self.setItem(0, 0, QTableWidgetItem('A'))
        self.setItem(0, 1, QTableWidgetItem('B'))
        self.setItem(0, 2, QTableWidgetItem('C'))
        self.setItem(0, 3, QTableWidgetItem('D'))
        self.setItem(0, 4, QTableWidgetItem('E'))
        self.setItem(0, 5, QTableWidgetItem('F'))
        self.setItem(0, 6, QTableWidgetItem('A'))
        self.setItem(0, 7, QTableWidgetItem('C'))
        self.setItem(0, 8, QTableWidgetItem('D'))

        for r in range(self.rowCount()):
            for c in range(self.columnCount()):
                item = QTableWidgetItem()
                self.item(r, c).setBackground(self.colour(self.item(r, c).text()))

    def colour(self, letter):

        if letter == 'A':
            colour = QColor(233, 12, 24)
        if letter == 'B':
            colour = QColor(12, 45, 67)
        if letter in ['C', 'E']:
            colour = QColor(23, 57, 188)
        if letter == 'F':
            colour = QColor(45, 116, 75)
        else:
            colour = QColor(233, 244, 12)
        return colour

def main():
    app = QApplication(sys.argv)
    window = QWidget()
    window.setGeometry(200,200,1200,400)
    tw = Table(window)
    twLayout = QVBoxLayout()
    twLayout.addWidget(tw)
    window.setLayout(twLayout)

    window.show()
    sys.exit(app.exec_())

if __name__ == '__main__':
    main()

当我运行它时，只有两种颜色最终出现在我的 table 中，其余的都被忽略了。我该如何修复它以及如何确保每个单元格根据其内容获得其独特的颜色？

Answer 1

在 Table.colour 的定义中，您有多个 if 语句，但 else 子句只会匹配其中的最后一个。你想要...

def colour(self, letter):
    if letter == 'A':
        colour = QColor(233, 12, 24)
    elif letter == 'B':
        colour = QColor(12, 45, 67)
    elif letter in ['C', 'E']:
        colour = QColor(23, 57, 188)
    elif letter == 'F':
        colour = QColor(45, 116, 75)
    else:
        colour = QColor(233, 244, 12)
    return colour

PyQt5：为什么我只能为 QTableWidget 单元格使用两种颜色？

PyQt5: why am I only able to use two colours for QTableWidget cells?

python

pyqt

qtablewidget

pyqt5