用 CHARINDEX 替换

Question

我有一个包含两个由“/”分隔的串联数据的列，我只想获取“/”之前等于另一个 table 的列的内容，所以我正在尝试将 SUBSTRING 与 CHARINDEX 一起使用，但我认为我做错了什么，请按照代码进行操作。

SELECT TOP 1 * FROM arquivo A, tabela_geral B (NOLOCK), campo_concatenado C (NOLOCK)
WHERE A.primeira_parte = SUBSTRING(C.concatenado, 1, CHARINDEX('/', C.concatenado) -1)
AND B.status = 0
AND B.campo = '13'
AND B.numero NOT IN (6, 78, 79, 80, 81, 82, 83, 91)

Answer 1

你试过吗？

 SELECT TOP 1 * FROM arquivo A, tabela_geral B (NOLOCK), campo_concatenado C (NOLOCK)
  WHERE A.primeira_parte = "%/"
  AND B.status = 0
  AND B.campo = '13'
  AND B.numero NOT IN (6, 78, 79, 80, 81, 82, 83, 91)

Answer 2

您应该处理没有“/”的行

如果您考虑“/”之前的值

SELECT TOP 1 * FROM arquivo A, tabela_geral B (NOLOCK), campo_concatenado C (NOLOCK)
WHERE A.primeira_parte = COALESCE(SUBSTRING(C.concatenado, 1, NULLIF(CHARINDEX('/', C.concatenado), 0) -1), C.concatenado)
AND B.status = 0
AND B.campo = '13'
AND B.numero NOT IN (6, 78, 79, 80, 81, 82, 83, 91)

如果你考虑'/'之后的值

SELECT TOP 1 * FROM arquivo A, tabela_geral B (NOLOCK), campo_concatenado C (NOLOCK)
WHERE A.primeira_parte = SUBSTRING(C.concatenado, 1, NULLIF(CHARINDEX('/', C.concatenado), 0) -1)
AND B.status = 0
AND B.campo = '13'
AND B.numero NOT IN (6, 78, 79, 80, 81, 82, 83, 91)

并且我强烈建议您关注 Sean Lange 的评论

用 CHARINDEX 替换

SUBSTRING WITH CHARINDEX

sql

sql-server

tsql

substring

charindex