在 TinkerPop 中顶点属性可以包含复杂的对象吗？

Question

我正在玩 TinkerGraph 和 gremlin-scala，我发现它能够持久化复杂对象：

case class InnerObj(a: Int, b: String)
case class ComplexObj(a: Int, b: InnerObj)
case class SuperComplexObj(a : String, b: ComplexObj)

class GremlinQueriesSpec extends FlatSpec
  with ScalaFutures with MustMatchers {

  behavior of "Gremlin queries"

  it must "be able to persist complex objects containing collections" taggedAs Integration in {

    val g = TinkerGraph.open()
    implicit val graph = g.asScala

    val user = RandomData.randomUserDataAggregate

    graph + user

    graph.V().toCC[UserDataAggregate].toList() must be eq List(user)
  }
}

然而，docs are not completely clear to me. On еру one hand there's not much structure available for property values besides lists, sets, and metaproperties. On the other hand docs say:

A Property denotes a key/value pair associated with an Edge. A property is much like a Java8 Optional in that a property can be not present (i.e. empty). The key of a property is always a String and the value of a property is an arbitrary Java object. Each underlying graph engine will typically have constraints on what Java objects are allowed to be used as values.

好的，看来要看实现了。但是可以在 Gremlin 查询中使用嵌套对象吗？

Answer 1

确实要看实现。您正在使用 TinkerGraph，它可以反过来存储任何 Java 对象，因此您可以自由地将任何您喜欢的东西放在那里：

gremlin> g.addV().property('function',{it.length()})
==>v[2]
gremlin> g.V().sideEffect{println(it.get().value('function')("four"))}
4
==>v[2]

疯了吧？当然，如果您开始在其中随机 odds/ends 并需要持久化这些对象或将它们推送到网络（例如通过 Gremlin 服务器），您将需要考虑序列化等问题。

嵌套对象作为 TinkerGraph 的值没有问题属性。只是要小心。在深入研究将复杂 Java 对象存储为属性的路径之前，真正停止考虑您的模式。也许最好将这些对象建模为图形的元素，作为第一个 class 公民，以使 Gremlin 遍历直接处理它们。

在 TinkerPop 中顶点属性可以包含复杂的对象吗？

In TinkerPop can vertex properties contain complex objects?

gremlin

tinkerpop

tinkerpop3