System.Windows.Forms.TextBox 不更改参考文本
System.Windows.Forms.TextBox does not change ref text
我将以下代码作为从 inputBox 获取输入的弹出对话框。我传入字符串作为参考,希望参考字符串会在对话框关闭时发生变化,这样我就可以获得用户输入。但是传入的字符串在对话框关闭时没有改变。我做错了什么?
public static DialogResult ShowInputDialog(ref string input1, ref string input2)
{
var size = new System.Drawing.Size(520, 180);
var inputBox = new Form { ClientSize = size };
var panel = new TableLayoutPanel
{
Size = new System.Drawing.Size(460, 180),
Location = new System.Drawing.Point(25, 15),
ColumnCount = 2,
RowCount = 3
};
// Add ColumnStyles/RowStyles here
panel.Controls.Add(new Label { Text = "Input 1", TextAlign = ContentAlignment.BottomRight }, 0, 0);
panel.Controls.Add(new Label { Text = "Input2", TextAlign = ContentAlignment.BottomRight }, 0, 1);
panel.Controls.Add(new TextBox { Text = input1, Width = 280 }, 1, 0);
panel.Controls.Add(new TextBox { Text = input2, Width = 280 }, 1, 1);
var okButton = new Button{ DialogResult = DialogResult.OK};
var cancelButton = new Button {DialogResult = DialogResult.Cancel};
var buttons = new FlowLayoutPanel();
buttons.Controls.Add(okButton);
buttons.Controls.Add(cancelButton);
panel.Controls.Add(buttons, 1, 3);
inputBox.Controls.Add(panel);
inputBox.AcceptButton = okButton;
inputBox.CancelButton = cancelButton;
var result = inputBox.ShowDialog();
return result;
}
以上代码的用法是:
string input1 = string.Empty;
string input2 = string.Empty;
ShowInputDialog(ref input, ref input2);
我不太熟悉 TableLayoutPanel
但也许你可以做一些简单的事情:
if (inputBox.ShowDialog() == DialogResult.OK)
{
input1 = (panel.GetControlFromPosition(1, 0) as TextBox).Text;
input2 = (panel.GetControlFromPosition(1, 1) as TextBox).Text;
return DialogResult.OK;
}
return DialogResult.Cancel;
您目前的问题是您实际上并没有在对话框关闭后的任何地方设置该值。
不过,我同意这个评论。一种 MVVM 模式可能会使维护(和创建)这些类型的属性及其各自的值变得更加容易。
用户单击确定按钮后,您必须将 textbox.text 值分配回 input1 和 input2
我将以下代码作为从 inputBox 获取输入的弹出对话框。我传入字符串作为参考,希望参考字符串会在对话框关闭时发生变化,这样我就可以获得用户输入。但是传入的字符串在对话框关闭时没有改变。我做错了什么?
public static DialogResult ShowInputDialog(ref string input1, ref string input2)
{
var size = new System.Drawing.Size(520, 180);
var inputBox = new Form { ClientSize = size };
var panel = new TableLayoutPanel
{
Size = new System.Drawing.Size(460, 180),
Location = new System.Drawing.Point(25, 15),
ColumnCount = 2,
RowCount = 3
};
// Add ColumnStyles/RowStyles here
panel.Controls.Add(new Label { Text = "Input 1", TextAlign = ContentAlignment.BottomRight }, 0, 0);
panel.Controls.Add(new Label { Text = "Input2", TextAlign = ContentAlignment.BottomRight }, 0, 1);
panel.Controls.Add(new TextBox { Text = input1, Width = 280 }, 1, 0);
panel.Controls.Add(new TextBox { Text = input2, Width = 280 }, 1, 1);
var okButton = new Button{ DialogResult = DialogResult.OK};
var cancelButton = new Button {DialogResult = DialogResult.Cancel};
var buttons = new FlowLayoutPanel();
buttons.Controls.Add(okButton);
buttons.Controls.Add(cancelButton);
panel.Controls.Add(buttons, 1, 3);
inputBox.Controls.Add(panel);
inputBox.AcceptButton = okButton;
inputBox.CancelButton = cancelButton;
var result = inputBox.ShowDialog();
return result;
}
以上代码的用法是:
string input1 = string.Empty;
string input2 = string.Empty;
ShowInputDialog(ref input, ref input2);
我不太熟悉 TableLayoutPanel
但也许你可以做一些简单的事情:
if (inputBox.ShowDialog() == DialogResult.OK)
{
input1 = (panel.GetControlFromPosition(1, 0) as TextBox).Text;
input2 = (panel.GetControlFromPosition(1, 1) as TextBox).Text;
return DialogResult.OK;
}
return DialogResult.Cancel;
您目前的问题是您实际上并没有在对话框关闭后的任何地方设置该值。
不过,我同意这个评论。一种 MVVM 模式可能会使维护(和创建)这些类型的属性及其各自的值变得更加容易。
用户单击确定按钮后,您必须将 textbox.text 值分配回 input1 和 input2