如何使用分层查询获取所有经理的列表

Question

我想提取担任我经理的员工名单。看看下面的查询：

SELECT   SYS_CONNECT_BY_PATH (username, ':') AS "Liste Membres",LEVEL
  FROM   employees
 WHERE   CONNECT_BY_ISLEAF = 1
         AND username = '150') -- My_code
START WITH   manager IS NULL
CONNECT BY   PRIOR username = manager

本次查询结果为：

:1:20:120:150

我想要得到的结果：

:1:20:120:

Answer 1

将其更改为 SYS_CONNECT_BY_PATH (manager, ':')，然后删除为根级别 NULL 管理器附加的前导 :（如果您想要尾随 :，则添加|| ':'):

SQL Fiddle

Oracle 11g R2 架构设置:

CREATE TABLE EMPLOYEES ( manager, username ) AS
  SELECT NULL, 1 FROM DUAL UNION ALL
  SELECT 1, 20 FROM DUAL UNION ALL
  SELECT 20, 120 FROM DUAL UNION ALL
  SELECT 120, 150 FROM DUAL;

查询 1:

SELECT   SUBSTR( SYS_CONNECT_BY_PATH (manager, ':'), 2 ) AS "Liste Membres",
         LEVEL
FROM     employees
WHERE    CONNECT_BY_ISLEAF = 1
AND      username = '150' -- My_code
START WITH   manager IS NULL
CONNECT BY   PRIOR username = manager

Results:

| Liste Membres | LEVEL |
|---------------|-------|
|     :1:20:120 |     4 |

如何使用分层查询获取所有经理的列表

How to get list of all manager using hierarchical query

oracle

hierarchical-query