Python: Pyppeteer 点击弹出 window

Question

我正在尝试接受在此 page 上生成的弹出窗口 window 上的 cookie 同意。我尝试使用 waitForSelector，但无头浏览器似乎可以看到我使用的选择器中的 none。我想实际切换到 "YES" 然后提交表格。我想它显示在 window.onload 上，所以可能需要在 JavaScript?

上完成

import asyncio
import time

from pyppeteer import launch
from pyppeteer.errors import TimeoutError
from urllib.parse import urlparse

URLS = [
    'https://www.trustarc.com/'
]

start = time.time()

async def fetch(url, browser):
    page = await browser.newPage()
    try:
        #await page.setRequestInterception(True)
        page.on('request', callback)
        await page.goto(url, {'waitUntil': 'networkidle0'})
        await page.screenshot({'path': f'img/{urlparse(url)[1]}.png', 'fullPage': True})
    except TimeoutError as e:
        print(f'Timeout for: {url}')
    finally:
        await page.close()


async def callback(req): 
    print(f'Request: {req.url}')

async def run():
    browser = await launch(headless=True, args=['--no-sandbox'])
    tasks = []

    for url in URLS:
        task = asyncio.ensure_future(fetch(url, browser))
        tasks.append(task)

    ret = await asyncio.gather(*tasks)
    await browser.close()

loop = asyncio.get_event_loop()
future = asyncio.ensure_future(run())
loop.run_until_complete(future)

print(f'It took {time.time()-start} seconds.')

Answer 1

如果 Cookie 首选项弹出框没有自动打开，您可以通过单击网页右下角的按钮手动打开弹出框。

cookie 选项位于 iframe 中，因此您必须等到框架内容加载后才能选择 "YES" 功能性 cookie 和广告 cookie。

提交首选项后，您需要等待并关闭确认消息才能继续使用网站。

完整示例：

// Navigate to the website

await page.goto( 'https://www.trustarc.com/', { 'waitUntil' : 'networkidle0' } );

// Open the Cookie Preferences pop-up (if necessary)

if ( await page.$( '.truste_overlay' ) === null )
{
    await page.click( '#teconsent > a' );
}

// Wait for the Cookie Preferences frame and content to load

const cookies_frame = page.frames()[1];

await cookies_frame.waitForSelector( '.active', { 'visible' : true } );

// Fill out and submit form

await cookies_frame.evaluate( () =>
{
    const yes_buttons   = document.getElementsByClassName( 'off' );
    const submit_button = document.getElementsByClassName( 'submit' )[0];

    yes_buttons[0].click();
    yes_buttons[1].click();

    submit_button.click();
});

// Wait for and close confirmation

const close_button = await cookies_frame.waitForSelector( '#gwt-debug-close_id' );

await close_button.click();

Answer 2

如果有人会觉得这有用，这是我的 Python 实现，基于已接受的答案：

import asyncio
import time

from pyppeteer import launch
from pyppeteer.errors import TimeoutError
from urllib.parse import urlparse

URLS = [
    'https://www.trustarc.com/'
]

start = time.time()

async def fetch(url, browser):
    page = await browser.newPage()
    try:
        #await page.setRequestInterception(True)
        #page.on('request', callback)
        await page.goto(url, {'waitUntil': 'networkidle0'})
        if not await page.J('.truste_overlay'):
            await page.click('#teconsent > a')
        cookies_frame = page.frames[1]
        await cookies_frame.waitForSelector( '.active', {'visible': True})
        await cookies_frame.evaluate('''() =>
            {
               const yes_buttons   = document.getElementsByClassName( 'off' );
               const submit_button = document.getElementsByClassName( 'submit' )[0];

               yes_buttons[0].click();
               yes_buttons[1].click();

               submit_button.click();
            }''')
        close_button = await cookies_frame.waitForSelector( '#gwt-debug-close_id' )
        await close_button.click()
        await page.screenshot({'path': f'img/{urlparse(url)[1]}.png', 'fullPage': True})
    except TimeoutError as e:
        print(f'Timeout for: {url}')
    finally:
        await page.close()


async def callback(req): 
    print(f'Request: {req.url}')

async def run():
    browser = await launch(headless=True, args=['--no-sandbox'])
    tasks = []

    for url in URLS:
        task = asyncio.ensure_future(fetch(url, browser))
        tasks.append(task)

    ret = await asyncio.gather(*tasks)
    await browser.close()

loop = asyncio.get_event_loop()
future = asyncio.ensure_future(run())
loop.run_until_complete(future)

print(f'It took {time.time()-start} seconds.')

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