获取未指定的值参数scala Kafka

Question

您好，我遇到了这个编译错误 -

Unspecified Value parameters: aggregator: (String, String, NotInferedVR) => NotInferedVR

但我显然已经有了一个聚合器。有谁知道怎么回事吗？

 val stream = builder
    .stream(inputTopic)(Consumed.`with`(Serdes.String(), Serdes.ByteArray()))
    .map{ (key: String, value: Array[Byte]) =>
      println(s"key = ${key}")
      val lv = GroupByAction.convertByteArrayToJsonObject(value)
      val lst = List.empty[String]
      val newKey = GroupByAction
        .reKey(lv
          , groupByColumnList
            .asScala
            .toList
          ,lst)
      val newValue = getValFromJSONMessage(lv, aggregateColumnList.asScala.toList.head)
      println(s"newKey = ${newKey}")
      (newKey, newValue)}
    .groupByKey(Serialized.`with`(Serdes.String(), Serdes.String()))
    .aggregate{ () => 0.toString, (k,v,vr: Long) => (v.toString.toLong + vr.toString.toLong).toString }

Answer 1

您只能使用 {} 形式的方法调用来传递单个参数，该参数被视为一个块。您需要传递两个参数，因此请改用 ()：

aggregate( () => 0.toString, (k,v,vr: Long) => (v.toString.toLong + vr.toString.toLong).toString )

获取未指定的值参数scala Kafka

Getting unspecified value parameter scala Kafka

dsl

scala

apache-kafka

apache-kafka-streams

kafka-streams-scala