获取从开始到结束数字之间的记录

Question

这 SQL return 来自 2 个表“posts_main”和“posts_comments”的所有记录（JSON）取决于特定用户

$sql = "select posts_main.*,
(select groupid from posts_comments where groupid = posts_main.id group by groupid ) as count_comments
from posts_main
WHERE posts_main.user_id = '$user_id' ";


$obj = json_decode($_GET["x"], false);
$stmt = $con->prepare($sql);
$stmt->bind_param("ss", $obj->table, $obj->limit);
$stmt->execute();
$result = $stmt->get_result();
$outp = $result->fetch_all(MYSQLI_ASSOC);

echo json_encode($outp);

我的问题： 如何获取前 10 条记录，然后是接下来的 10 条记录，直到最后？

例如： 我会发送 "start" = 0，我会得到前 10 条记录。下次我会发送："start" = 10，然后我会得到记录 FROM 10 TO 20。等等。

谢谢...

Answer 1

如果您有一个 "start" 号码，您可以像这样构建您的查询 -

$sql = "select posts_main.*,
(select groupid from posts_comments where groupid = posts_main.id group by groupid ) as count_comments
from posts_main
WHERE posts_main.user_id = '$user_id' limit 10,10";

MySQL 从 table 中的第 11 条记录开始读取 10 条记录。如果您正在寻找 Prev, Next 解决方案，那么 PHP 分页是唯一的选择。

Answer 2

希望对您有所帮助：

$start = 0;
$sql = "select posts_main.*,
(select groupid from posts_comments where groupid = posts_main.id group by groupid ) as count_comments
from posts_main
WHERE posts_main.user_id = '$user_id' 
limit '$start' 10";

获取从开始到结束数字之间的记录

get records between from a start to end number

php

mysql

json

record

between