JS:如何防止 let 重复声明? / 判断是否定义了 let 变量

JS: How to prevent let double declaration? / determine if let variable is defined

如果我打开 JS 控制台并写入:

let foo;

及之后:

let foo = "bar"

控制台告诉我(正确)

Uncaught SyntaxError: Identifier 'foo' has already been declared

现在...有时我需要将我的代码注入到现有脚本中,但我没有工具来确定是否已经定义了 let 变量。

我尝试使用这段代码,但 JS 范围和逻辑存在明显问题....(评论代码)

let foo; // Gloabl variable empty declare in a code far, far away 

console.log(foo); // undefined

console.log(typeof foo === "undefined"); // test that determinate if condition is true

if(typeof foo === "undefined"){
    let foo = "test";
    console.log(foo); // return "test" this means that foo as a local scope only inside this if... 
}

console.log(foo); // return undefined not test!

// and .. if I try to double declaration... 
 let foo = "bar"; //error!

所以...如何防止双重 "let" 声明? / 如何确定一个 let var 是否被定义(声明?)

P.S "var" 一切正常!!!

您可以为脚本定义范围。您仍然可以访问该范围内的外部变量。

let toto = 42;
let foo = "bar";
   
console.log(toto);
   
//Some added script
{
    let toto = "hello world !";
    console.log(toto);
    console.log(foo);
}
//back to main script
console.log(toto);

您仍然可以使用 try - catch 以编程方式检查变量是否存在,但是在 try { } catch { } 范围内声明变量可能非常棘手

let existingVariable = "I'm alive !";

try
{
    console.log("existingVariable exists and contains : " + existingVariable);
    console.log("UndeclaredVariable exists and contains : " + UndeclaredVariable);
}
catch (ex)
{
    if (ex instanceof ReferenceError)
    {
        console.log("Not good but I caught exception : " + ex);
    }
}
console.log("Looks like my script didn't crash :)");

如果您不想创建一个新范围来确保您的变量不存在于现有脚本中,那么...为它们添加前缀 let r1sivar_userinput