有效地连接地址行

Question

我的数据库存储了一些标准地址行字段（地址行 1,2.. 城市、国家/地区，Postal/zip 代码），我想将它们连接成人类形式。我已经编写了以下代码，但我不确定使用一堆 if 语句是否非常有效。（写在python不过是我关心的算法）

def human_readable_address(self):
    '''
    Return human readable address
    If address1 is empyty, return None
    '''
    addr = ""

    if(self.address1):
        addr += self.address1 + ", "
    else:
        return None

    if(self.address2):
        addr += self.address2 + ", "
    if(self.city):
        addr += self.city + ", "
    if(self.postal_code):
        addr += self.postal_code + ", "
    if(self.country):
        addr += self.country + ", "

    return addr

大家怎么看？有没有更好的方法？

Answer 1

您可以使用 str.join():

而不是使用字符串连接（每次都会创建一个新字符串）

def human_readable_address(self):
    '''
    Return human readable address
    If address1 is empty, return None
    '''

    if not self.address1:
        return None

    return ', '.join(filter(None, [self.address1, self.address2, self.city,
                                   self.postal_code, self.country]))

Answer 2

您可以使用列表理解，连接成一个字符串，以您需要的格式获取地址：

address_1 = "first"
address_2 = False
address_3 = "third"

def make_address(*args):
  return "".join(["%s,\n" % x for x in args if x])[:-2]

address = make_address(address_1, address_2, address_3)

print(address)

如：https://repl.it/repls/LiveJuniorLanservers

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