如何在 flutter 中更改应用栏标题

Question

**change the appbar title dynamically**

正在从数据库中获取应用栏标题，然后我必须设置为应用栏。我也是 flutter 的新手，也尝试过 setState。

我试过 setState() as 但还是不行。我如何根据服务器响应和数据库值更改应用栏文本

import 'dart:async';

import 'package:flutter/material.dart'; 
import 'package:parking_app/data/database_helper.dart'; 
import'package:parking_app/models/user.dart';

class HomeScreen extends StatefulWidget {   @override   State<StatefulWidget> createState() {
    return new HomeScreenState();   } }

class HomeScreenState extends State<HomeScreen> {   @override   Widget build(BuildContext context) {
    var db = new DatabaseHelper();
    Future<User> user = db.getUser();
    String appBarTitle = "eClerx Parking";
    var appBarTitleText = new Text(appBarTitle);

if (user != null) {
  user.then((val) {
    if (val == null) {
      return;
    }
    print(TAG+ "  user data : " + val.emailId);
    setState(() {
      build(context);
      appBarTitle = val.emailId;
    });
  });
}

return new MaterialApp(
  home: new Scaffold(
    appBar: new AppBar(
      title: appBarTitleText,
      actions: <Widget>[
        // action button
        new IconButton(
          icon: new Icon(Icons.settings_power),
          onPressed: () {
            _logout();
          },
        ),
        // action button
      ],
    ),
    body: new Padding(
      padding: const EdgeInsets.all(16.0),
      child: new ChoiceCard(choice: choices[0]),
    ),
  ),
);   } }

Answer 1

改变

appBarTitle = val.emailId

至

setState(() {
  appBarTitle = val.emailId;
});

Answer 2

您也可以拆分代码，假设您的数据库提取是异步的。

class HomeScreenState extends State<HomeScreen> {
     var appBarTitleText = new Text("eClerx Parking");

     Future getUser() async {
        var user = await db.getUser();

        if (user != null) {
           user.then((val) {
              if (val == null) {
                return;
              }
              print("user data : " + val.emailId);

              setState(() {
                appBarTitleText = Text(val.emailId);
             });
           });
        }
    }


    @override
       void initState() {
       super.initState();
       getUser();
    }

    @override
    Widget build(BuildContext context) {
    ...

Answer 3

您不应该在构建函数中执行所有操作。每次调用 setState 时构建函数都会重绘，因此每次重绘时都会启动 String appBarTitle = "eClerx Parking";。

您需要覆盖 initState() 并将此逻辑放在那里

var db = new DatabaseHelper();
    Future<User> user = db.getUser();
    String appBarTitle = "eClerx Parking";
    var appBarTitleText = new Text(appBarTitle);


if (user != null) {
  user.then((val) {
    if (val == null) {
      return;
    }
    print("user data : " + val.emailId);
    //DO THIS TO UPDATE THE STATE AND FORCE A REDRAW
    setState(() {
      appBarTitle = val.emailId;
    });
  });

此外，用 setState() 函数包裹 appBarTitle = val.emailId;

编辑：您不是在等待数据库的结果Future<User> user = db.getUser();，因此用户将始终为 null 并且 setState 永远不会被调用。

尝试Future<User> user = await db.getUser();

Answer 4

create global variable name it appBar Title inside statefulwidget state class

var appBarTitle ="some text";

并为其分配 appBar 标题

然后用setState方法改变它的值

如何在 flutter 中更改应用栏标题

How to change the app bar title in flutter

appbar

flutter