排序数组指定索引 IOS
sort array specified indexes IOS
我想根据名为 id 的对象过滤 NSARRAY
,我有一组我想要过滤的特定 ID,并希望成为 NSARRAY
中的第一个。
我将以下 ID 存储为 NSNUMEBR
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
这些是我要过滤的id集合,希望在我的NSARRAY
中排在第一位(可以是NSMutableArray
进行操作)
编辑 1:
NSARRAY 基本上是获取 id 对象作为
Ids = [dict valueForKey:@"id"];
选择性 ID 存储在 NSNUMBER A 到 I
不清楚您的问题,如反对票和评论所示。但是让我们看看我们是否能提供帮助。我认为以下伪代码算法是您所要求的:
MutableArray frontItems, rearItems;
for every item in sourceArray
if item["id"] is in the collection of specific IDs
then add item to end of frontItems
else add item to end of rearItems
add rearItems to end of frontItems to give result
在Objective-C中写下,我想你已经得到了你想要的。
HTH
//创建包含所有项的数组:A->I
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
NSMutableArray *arr = [[NSMutableArray alloc] initWithObjects:A,B,C,...,I, nil];
for (NSNumber *idx in arr) {
// To do
}
我想根据名为 id 的对象过滤 NSARRAY
,我有一组我想要过滤的特定 ID,并希望成为 NSARRAY
中的第一个。
我将以下 ID 存储为 NSNUMEBR
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
这些是我要过滤的id集合,希望在我的NSARRAY
中排在第一位(可以是NSMutableArray
进行操作)
编辑 1:
NSARRAY 基本上是获取 id 对象作为
Ids = [dict valueForKey:@"id"];
选择性 ID 存储在 NSNUMBER A 到 I
不清楚您的问题,如反对票和评论所示。但是让我们看看我们是否能提供帮助。我认为以下伪代码算法是您所要求的:
MutableArray frontItems, rearItems;
for every item in sourceArray
if item["id"] is in the collection of specific IDs
then add item to end of frontItems
else add item to end of rearItems
add rearItems to end of frontItems to give result
在Objective-C中写下,我想你已经得到了你想要的。
HTH
//创建包含所有项的数组:A->I
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
NSMutableArray *arr = [[NSMutableArray alloc] initWithObjects:A,B,C,...,I, nil];
for (NSNumber *idx in arr) {
// To do
}