幂和平方根不适用于 C++ 中的 assert()

Question

这里显示了两个函数： https://pastebin.com/QWQ6yH6u

// main() calls both findDistance() and test() correctly so they don't need to be shown.
// Note: This is only a section of the full code as it is the only relevant part.

double findDistance(float x1, float y1, float x2, float y2) {
    double distanceTotal = sqrt( pow( 2, (x2-x1) ) + pow( 2, (y2-y1) )); // This line doesn't work with assert values.
    //double distanceTotal = (x2-x1) + (y2-y1); // This line works with assert values.
    return distanceTotal;
}

void test() {
    assert(findDistance(4, 3, 5, 1) - 2.23607 <= epsilon);
    assert(findDistance(2, 4, 2, 4) <= 1.00);
    assert(findDistance(4, 4, 4, 4) <= 1.00);

    cout << "all tests passed..." << endl;
}

findDistance 函数正在计算两点 (x1, y1), (x2, y2) 之间的距离。一行与 assert() 值一起正常工作，而包含平方根和幂的那一行则不能。第 5 行有什么问题？

代码使用 http://cpp.sh 编译成功，当前代码的输出为：

Do you want to run the program? (y/n) y
Program calculates distance between 2 points on a 2D coordinates.
Enter a point in the form (x, y): (3,3)
(x1, y1) = (3.00, 3.00) 
Enter a second point in the form (x, y): (1,1)
(x2, y2) = (1.00, 1.00)

我已经查看了以下帖子： 1. 2. Square root line doesn’t work 3.

Answer 1

错误是由于std::pow()的错误使用造成的。这应该会更好：

double distanceTotal = sqrt( pow( (x2-x1),2 ) + pow( (y2-y1), 2 )); // This line doesn't work with assert values.

Online demo

幂和平方根不适用于 C++ 中的 assert()

Power and Square Root not working with assert() in C++

c++

sqrt

pow