确切的论点与 Minitest 模拟期望相匹配?

Exact argument matches with Minitest mock expectations?

我正在编写 Minitest 单元测试,需要检查被测代码是否从 HTTP 响应模拟中提取了特定的哈希值。所以我设定了以下期望:

@http_response.expect :[], 3141, [ "X-Pagination-TotalElements" ]
@http_response.expect :[], 32, [ "X-Pagination-TotalPages" ]

然而匹配似乎是基于大小写相等的,第二个期望覆盖第一个。

完成我想做的事情的正确方法是什么?

However it seems that matching is based on case equality [===]

...对于字符串 class 与 == 相同。

the second expectation overrides the first.

看来 expect statements 的顺序对于 MiniTest::Mock 个对象很重要:

require 'minitest/autorun'

resp = MiniTest::Mock.new
resp.expect :[], 3141, ["X-Pagination-TotalElements"]
resp.expect :[], 32, ["X-Pagination-TotalPages"]

puts resp["X-Pagination-TotalElements"]
puts resp["X-Pagination-TotalPages"]

--output:--
3141
32
Run options: --seed 29457

# Running:

Finished in 0.001500s, 0.0000 runs/s, 0.0000 assertions/s.

0 runs, 0 assertions, 0 failures, 0 errors, 0 skips

但这失败了:

require 'minitest/autorun'

resp = MiniTest::Mock.new
resp.expect :[], 3141, ["X-Pagination-TotalElements"]
resp.expect :[], 32, ["X-Pagination-TotalPages"]

puts resp["X-Pagination-TotalPages"]
puts resp["X-Pagination-TotalElements"]

--output:--
/Users/7stud/.rvm/gems/ruby-2.1.2/gems/minitest-5.4.0/lib/minitest/mock.rb:148:in method_missing': mocked method :[] called with unexpected arguments ["X-Pagination-TotalPages"] (MockExpectationError) from 1.rb:7:in '

并且数量也发挥了作用:

require 'minitest/autorun'

resp = MiniTest::Mock.new
resp.expect :[], 3141, ["X-Pagination-TotalElements"]

puts resp["X-Pagination-TotalElements"]
puts resp["X-Pagination-TotalElements"]

--output:--
3141

/Users/7stud/.rvm/gems/ruby-2.1.2/gems/minitest-5.4.0/lib/minitest/mock.rb:122:in method_missing': No more expects available for :[]: ["X-Pagination-TotalElements"] (MockExpectationError) from 1.rb:7:in '

结果,意思是:

resp.expect :[], 3141, ["X-Pagination-TotalElements"]
resp.expect :[], 32, ["X-Pagination-TotalPages"]

..是:

  1. 我希望最初使用键 "X-Pagination-TotalElements" 调用 resp[] 将 return 3141。

  2. 我希望使用密钥 "X-Pagination-TotalPages" 再次调用 resp[] 将 return 32。

  3. 我预计任何额外的调用或不按该顺序调用都会导致失败。

...

What is the correct way to accomplish what I am trying to do?

按照将在您的代码中调用的顺序添加 expect 语句。