当我尝试浏览 .xlsx 文件时，会打开一个新的 Excel 文档

Question

我目前正在使用 PyQt5 开发 GUI。我正在使用菜单栏加载文件，当我单击它时，程序会调用此函数：

   def getxlsbase(self):
        filePath_base, _ = QtWidgets.QFileDialog.getOpenFileName(self, 'Select file', './', 'Excel Files (*.xls *.xlsx)')
        base = xlrd.open_workbook(filePath_base)
        hoja_base = base.sheet_by_index(0)
        num_row = hoja_base.nrows
        num_col = hoja_base.ncols

当浏览器 window 打开并且我 select 文件时，一个空白的 Excel 文档打开，我该如何避免这种情况？

编辑：我试过这个方法，但我仍然有这个问题，它只发生在 excel 文档中。我正在使用 Spyder3

from tkinter import *
from tkinter import filedialog

root = Tk()
root.withdraw()
filepath = filedialog.askopenfilename()
print(filepath)

Answer 1

您提供的方法正确。

import sys
import xlrd
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
from PyQt5.QAxContainer import QAxWidget

class AxWidget(QWidget):    

    def __init__(self, *args, **kwargs):
        super(AxWidget, self).__init__(*args, **kwargs)
        self.resize(800, 600)
        layout = QVBoxLayout(self)
        self.axWidget = QAxWidget(self)
        layout.addWidget(self.axWidget)
        layout.addWidget(QPushButton('Select file', self, clicked=self.getxlsbase))

    def getxlsbase(self):
        filePath_base, _ = QFileDialog.getOpenFileName(self, 
                                     'Select file', 
                                     './', 
                                     'Excel Files (*.xls *.xlsx)')
        print("filePath_base->", filePath_base)                             
        base = xlrd.open_workbook(filePath_base)
        print("base->", base) 
        hoja_base = base.sheet_by_index(0)
        print("hoja_base->", hoja_base)
        num_row = hoja_base.nrows
        print("num_row->", num_row)
        num_col = hoja_base.ncols
        print("num_col->", num_col)

        return self.openOffice(filePath_base, 'Excel.Application')

    def openOffice(self, path, app):
        self.axWidget.clear()
        if not self.axWidget.setControl(app):
            return QMessageBox.critical(self, 'Error', 'No installation  %s' % app)
        self.axWidget.dynamicCall(
            'SetVisible (bool Visible)', 'false')         
        self.axWidget.setProperty('DisplayAlerts', False)
        self.axWidget.setControl(path)        

    def closeEvent(self, event):
        self.axWidget.close()
        self.axWidget.clear()
        self.layout().removeWidget(self.axWidget)
        del self.axWidget
        super(AxWidget, self).closeEvent(event)        


if __name__ == '__main__':
    app = QApplication(sys.argv)
    ex  = AxWidget()
    ex.show()
    sys.exit(app.exec_())

Answer 2

我不知道我是否理解正确的问题，但是如果像我一样，当您打开一个 excel 文档时，一个 window 打开并带有一个文件选择，那么您可以这样做这个：

    def get_path_excel_file(self):
        excel_path, _ = QFileDialog.getOpenFileName(self,
                                                   'Select file',
                                                   './',
                                                   'Excel Files (*.xls *.xlsx)')
        # assign a path to some element
        self.label_5.setText(f"{excel_path}")
    
    # we get the path from this element
    book = openpyxl.load_workbook(fr"{self.label_5.text()}")

当我尝试浏览 .xlsx 文件时，会打开一个新的 Excel 文档

When I try to browse for a .xslx file a new Excel document opens

python

tkinter

xlrd

pyqt5