如何减少 stackexchange api 的查询时间?

How to reduce query time for stackexchange api?

我尝试为用户列表收集问题。

所以我准备了这个命令行:

library(stackr)
dft <- data.frame()
for (j in 1:nrow(df)) {
     questions <- stack_users(df$userid[j], "questions", num_pages=1000000, pagesize=100, filter="withbody")                
    for (s in 1:nrow(questions)){
      dft <- rbind(dft, data.frame(
        tags               = ifelse(is.null(questions$tags[s])               , NA, questions$tags[s]),
        is_answered        = ifelse(is.null(questions$is_answered[s])        , NA, questions$is_answered[s]),
        view_count         = ifelse(is.null(questions$view_count[s])         , NA, questions$view_count[s]),
        accepted_answer_id = ifelse(is.null(questions$accepted_answer_id[s]) , NA, questions$accepted_answer_id[s]),
        answer_count       = ifelse(is.null(questions$answer_count[s])       , NA, questions$answer_count[s]),
        score              = ifelse(is.null(questions$score[s])              , NA, questions$score[s]),
        last_activity_date = ifelse(is.null(questions$last_activity_date[s]) , NA, questions$last_activity_date[s]),
        creation_date      = ifelse(is.null(questions$creation_date[s])      , NA, questions$creation_date[s]),
        last_edit_date     = ifelse(is.null(questions$last_edit_date[s])     , NA, questions$last_edit_date[s]),
        question_id        = ifelse(is.null(questions$question_id[s])        , NA, questions$question_id[s]),
        link               = ifelse(is.null(questions$link[s])               , NA, questions$link[s]),
        title              = ifelse(is.null(questions$title[s])              , NA, questions$title[s]),
        body               = ifelse(is.null(questions$body[s])               , NA, questions$body[s]),
        owner_reputation   = ifelse(is.null(questions$owner_reputation[s])   , NA, questions$owner_reputation[s]),
        owner_user_id      = ifelse(is.null(questions$owner_user_id[s])      , NA, questions$owner_user_id[s]),
        owner_user_type    = ifelse(is.null(questions$owner_user_type[s])    , NA, questions$owner_user_type[s]),
        owner_accept_rate  = ifelse(is.null(questions$owner_accept_rate[s])  , NA, questions$owner_accept_rate[s]),
        owner_link         = ifelse(is.null(questions$owner_link[s])         , NA, questions$owner_link[s])
      ))

    }       

}

但是收集不同用户 ID 的列表需要很长时间。有什么方法可以减少执行时间或更新我可以制作的代码吗?

部分答案,因为我不流利 r:

您是否要获取一组给定用户的问题列表?

如果是,

for (j in 1:nrow(df)) {
    questions <- stack_users(df$userid[j]... 

是一种糟糕的方法。

参考the API's /users/{ids}/questions doc:

(The) {ids} (parameter) can contain up to 100 semicolon delimited ids. To find ids programmatically look for user_id on user or shallow_user objects.

(已强调)

因此,而不是计算结果为 stack_users(1,...(一个 id)

为该功能将 ID 以 100 个为一组进行分组。类似于:

stack_users(c(1,2,3,4,5,...),...

(但请记住我不是 r 编码员。)