改变骰子的眼睛

Change the eye of a dice

学校给我的作业是制作一个用户可以改变骰子眼睛的骰子游戏,他们给我的唯一提示是使用 ASCII table..

到目前为止,这是我的代码,我遇到了困难,因为我无法让数字成为用户的输入(我不是很有创意):

 System.out.println("Which character should be used as the eye of the dice:");
    char eyeDice = input.next().charAt(0);
    System.out.println(eyeDice);


    int Dice;
    Dice = (int)(Math.random()* 6 + 1);

    while (Dice < 6) {
        Dice = (int)(Math.random()* 6 + 1);
        System.out.println(Dice);

    }

代码的输出如下所示:

Which character should be used as the eye of the dice:
$
$
1
4
1
1
1
1
4
1
2
2
6

Process finished with exit code 0

最终应该是这样的:

Which character should be used as the eye of the dice:

#
  #
    #

#   #
  #
#   #

#   #

#   #
#   #
#   #


Process finished with exit code 0

任何正确方向的提示或暗示将不胜感激!

计算机未附带将数字“4”转换为 ascii 图形的代码。

你必须自己写这个。我建议把这些画在一张纸上。在您的 java 代码中,您可以有一堆 if/elseif 语句,每个语句对应 6 个面孔。每个块将打印 3 行。首先锁定用于眼睛的角色,然后努力使用户可以稍后配置。

以下是帮助您入门的部分内容:

if (dieRoll == 5) {
    System.out.println("* *");
    System.out.println(" * ");
    System.out.println("* *");
} else if (dieRoll == 6) {
    // you figure it out from here...

在给定的示例中,eyeDice'#'。抛出的 dice(请在 java 中加上一个小的 d)将是 3、5、4 和 6。

因此你需要一些方法,比如:

void printDice(int dice, char eyDice) {
    ... System.out.println ...
}

和您的代码

int dice = (int)(Math.random()* 6 + 1);

while (dice < 6) {
    printDice(dice, eyeDice);
    dice = (int)(Math.random()* 6 + 1)
}

将打印 5(忽略眼睛):

System.out.println("?   ?");
System.out.println("  ?  ");
System.out.println("?   ?");

这不是一个完整的示例,但它可以让您了解该怎么做

public static void main(String[] args){
    System.out.println("Which character should be used as the eye of the dice:");
    char eyeDice = input.next().charAt(0);
    System.out.println(eyeDice);


    int Dice;
    Dice = (int)(Math.random()* 6 + 1);

    while (Dice < 6) {
        Dice = (int)(Math.random()* 6 + 1);
        System.out.println(Dice);
        //If statement calling print
    }
}

private void printOne(char character){
    String dice = "\n  #  \n";
    System.out.println(dice.replace('#', character));
}

private void printTwo(char character){
    String dice = "#   #\n\n#   #";
    System.out.println(dice.replace('#', character));
}

private void printThree(char character){
    String dice = "#\n  #\n   #";
    System.out.println(dice.replace('#', character));
}

我知道您已经有了答案,但另一种可能的解决方案是使用 ENUM。例如:

public class Dice 
{
    private enum DieFace
    {
        ONE('1', "   \n * \n   "),
        TWO('2', "*  \n   \n  *"),
        THREE('3', "*  \n * \n  *"),
        FOUR('4', "* *\n   \n* *"),
        FIVE('5', "* *\n * \n* *"),
        SIX('6', "* *\n* *\n* *");

        private char characterCode;
        private String representation;

        DieFace(char characterCode, String representation)
        {
            this.characterCode = characterCode;
            this.representation = representation;
        }

        public static DieFace getDieFaceFromCharacterCode(char characterCode)
        {
            DieFace dieFaceFound = null;

            for (DieFace dieFace : values())
            {
                if (dieFace.characterCode == characterCode)
                {
                    dieFaceFound = dieFace;
                    break;
                }
            }

            return dieFaceFound;
        }

        @Override
        public String toString()
        {
            return this.representation;
        }
    }

    public static String getDieFaceFromCharacter(char characterInput)
    {
        DieFace dieFace = DieFace.getDieFaceFromCharacterCode(characterInput);

        return dieFace == null ? null : dieFace.toString();
    }
}

这里是 class 的测试:

public class DieTest 
{
    @Test
    public void testGetOne()
    {
        String expectedResult = "   \n * \n   ";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('1'));
    }

    @Test
    public void testGetTwo()
    {
        String expectedResult = "*  \n   \n  *";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('2'));
    }

    @Test
    public void testGetThree()
    {
        String expectedResult = "*  \n * \n  *";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('3'));
    }

    @Test
    public void testGetFour()
    {
        String expectedResult = "* *\n   \n* *";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('4'));
    }

    @Test
    public void testGetFive()
    {
        String expectedResult = "* *\n * \n* *";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('5'));
    }

    @Test
    public void testGetSix()
    {
        String expectedResult = "* *\n* *\n* *";
        assertEquals(expectedResult, Dice.getDieFaceFromCharacter('6'));
    }

    @Test
    public void testGetInvalid()
    {
        // < 1 is invalid
        assertNull(Dice.getDieFaceFromCharacter('0'));

        // invalid character (non-number)
        assertNull(Dice.getDieFaceFromCharacter('a'));

        // > 6 is invalid
        assertNull(Dice.getDieFaceFromCharacter('7'));
    }
}

简单的骰子程序

import java.util.Random;
public class Program
{
public static void main(String[] args) {
Random input =new Random();
    int a = 3;
    int b = 6;
    int c =input.nextInt(b-a)+a;

    switch(a){
       case 2:
       System.out.println("*");
       break;
       case 5:
       System.out.println("*  *");
       break;
       case 6:
       System.out.println("* \n * \n  *");
       break;
      case 4:
       System.out.println("*  * \n*  *");
       break;
       case 1:
       System.out.println("*   *\n  *\n*   *");
       break;
       case 3:
       System.out.println(" *  *  *\n\n *  *  *");
       break;


           }
    }
}

如果您希望尽量减少重用,可以使用 switch 语句。例如:

public class Dice 
{
    private static final String LINE_BREAK = "\n";
    public static String getDieFaceFromCharacter(char characterInput)
    {
        String top = "   ";
        String middle = "   ";
        String bottom = "   ";

        switch(characterInput)
        {
            case '5':
                top = "* *";
                bottom = "* *";
            case '1':
                middle = " * ";
                break;
            case '3':
                top = "*  ";
                middle = " * ";
                bottom = "  *";
                break;
            case '2':
                top = "*  ";
                bottom = "  *";
                break;
            case '6':
                middle = "* *";
            case '4':
                top = "* *";
                bottom = "* *";
        }

        return top + LINE_BREAK + middle + LINE_BREAK + bottom;
    }
}