Ruby 计数笑脸 - 退出代码 = 1

Question

Codewars 上的计数笑脸问题，我的代码通过了所有测试，但是 "Exit Code = 1" 错误消息一直弹出，这是什么意思？什么地方出了错？

countSmileys([':)', ';(', ';}', ':-D']);       // should return 2;
countSmileys([';D', ':-(', ':-)', ';~)']);     // should return 3;
countSmileys([';]', ':[', ';*', ':$', ';-D']); // should return 1;

    def count_smileys(arr)
      first = ";:"
      second = "-~"
      third = ")D"
      arr.select{|x|
        third.include?(x[1]) or (second.include?(x[1]) && third.include?(x[2].to_s)) 
      }.count
    end

编辑： 错误信息如下：

main.rb:8:in `include?': no implicit conversion of nil into String (TypeError)
    from main.rb:8:in `block in count_smileys'
    from main.rb:7:in `select'
    from main.rb:7:in `count_smileys'
    from main.rb:16:in `block in <main>'
    from /runner/frameworks/ruby/cw-2.rb:55:in `block in describe'
    from /runner/frameworks/ruby/cw-2.rb:46:in `measure'
    from /runner/frameworks/ruby/cw-2.rb:51:in `describe'
    from main.rb:11:in `<main>'

Answer 1

如消息所述，没有从 nil 到字符串的隐式转换。虽然明确存在：

2.3.1 :001 > nil.to_s
=> ""

您可以先为 nil 解析您的数组，然后通过 select 方法将其放入。

def count_smileys(arr)
  first = ";:"
  second = "-~"
  third = ")D"

  # parse your array for nil values here
  arr.map {|x| x.nil? ? "" : x }

  arr.select{|x|
    third.include?(x[1]) or (second.include?(x[1]) && third.include?(x[2].to_s)) 
  }.count
end

Answer 2

我意识到问题所在 - 有一个测试 count_smileys([";", ")", ";*", ":$", "8-D"])，其中 x[1] 和 x[2] 对数组中的前 2 项无效，所以我需要修复select 方法中的数组：

def count_smileys(arr)
  first = ";:"
  second = "-~"
  third = ")D"
  arr.select{|x|
    x[1] = " " if x[1] == nil
    x[2] = "" if x[2] == nil
    (first.include?(x[0]) && third.include?(x[1])) || (first.include?(x[0]) && second.include?(x[1]) && third.include?(x[2])) 
  }.count
end

Joseph Cho 在需要转换 nils 的意义上是正确的，但我们应该在迭代中进行转换，并且公共项目 x[1] 应该设置为带有 space 的空字符串避免被计算在内，而 x[2] 并不常见，空字符串也可以。

Ruby 计数笑脸 - 退出代码 = 1

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