XSLT 中的条件分组

Question

请求您帮助使用 XSLT 2

转换 XML

我的输入 XML 如下所示。

    <?xml version="1.0" encoding="UTF-8"?>
<Workers>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>A</type>
            <name>New York</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>B</type>
            <name>Boston</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>78698</Batch_number>
        <Name>Karen</Name>
        <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
    </Worker>
</Workers>

所需的输出如下所示。

<?xml version="1.0" encoding="UTF-8"?>
<Worker>
    <Batch_number>1234</Batch_number>
    <Name>David</Name>
    <Assignment>
            <type>A</type>
            <name>New York</name>
        </Assignment>
    <Assignment>
            <type>B</type>
            <name>Boston</name>
        </Assignment>
    <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
</Worker>
<Worker>
    <Batch_number>78698</Batch_number>
    <Name>Karen</Name>
    <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
</Worker>

转换条件为：

如果输入文件中存在具有相同 <Batch_number> 的子节点 <Worker>，则相同 <Batch_number> 的所有 Assignment 节点应归为一个 Worker <Batch_number> 和 <Name>

之后的子节点

有人可以帮我写正确的代码来实现这个吗？

Answer 1

虽然您想要的输出 XML 不是 格式良好的 ，但这里有一个 XSLT-2.0 解决方案可以满足您的特殊需求：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/Workers">
        <xsl:for-each-group select="Worker" group-by="Batch_number">
            <Worker>
                <Batch_number><xsl:value-of select="current-grouping-key()" /></Batch_number>
                <Name><xsl:value-of select="current()/Name" /></Name>
                <xsl:copy-of select="current-group()/Assignment" />
            </Worker>
        </xsl:for-each-group>
    </xsl:template>

</xsl:stylesheet>

它的输出是：

<?xml version="1.0" encoding="UTF-8"?>
<Worker>
    <Batch_number>1234</Batch_number>
    <Name>David</Name>
    <Assignment>
        <type>A</type>
        <name>New York</name>
    </Assignment>
    <Assignment>
        <type>B</type>
        <name>Boston</name>
    </Assignment>
    <Assignment>
        <type>C</type>
        <name>Chicago</name>
    </Assignment>
</Worker>
<Worker>
    <Batch_number>78698</Batch_number>
    <Name>Karen</Name>
    <Assignment>
        <type>C</type>
        <name>Chicago</name>
    </Assignment>
</Worker>

XSLT 中的条件分组

Conditional grouping in XSLT

xpath

xslt-2.0

muenchian-grouping