你如何比较 JS 中的 "week-year" 值？

Question

例如，我有以下 String 周-年格式的值：

// week-year
"8-18" < "9-18"   // returns true
"8-18" < "10-18"  // returns false but should return true
"8-18" < "4-18"   // returns false but should be true

为了调度目的，我必须整理出一组具有 "week-year" 值的数组。目前我正在使用 array.sort 来完成这个：

var results = [
  [ 
    { weekyear:"4-18" } 
  ], 
  [
    { weekyear:"5-18" }
  ], 
  [
    { weekyear: "1-19" }
  ] ... ]

results.sort((function (index) { // Sort based on Week-Year in descending order 
  return function (a, b) {
    return (a[index].weekyear === b[index].weekyear ? 0 : (a[index].weekyear< b[index].weekyear ? -1 : 1));
  };
})(0));

有什么方法可以将 week-year 值修改为允许排序的数值吗？

以上排序应该给我的顺序是：

"1-19" , "5-18" , "4-18"

Answer 1

您可以创建一个格式化的字符串，其中年份在前，然后是填充的周，可以将其作为字符串进行比较。

function getYearWeek(weekYear) {
    return weekYear
        .split('-')
        .map(s => s.padStart(2, '0'))
        .reverse()
        .join('-W');
}

var results = [{ weekyear: "4-20" }, { weekyear: "5-18" }, { weekyear: "4-18" }, { weekyear: "1-19" }];

console.log(getYearWeek("8-18") < getYearWeek("9-18"));  // true
console.log(getYearWeek("8-18") < getYearWeek("10-18")); // true
console.log(getYearWeek("8-18") < getYearWeek("4-18"));  // false

results.sort((a, b) => 
    getYearWeek(a.weekyear).localeCompare(getYearWeek(b.weekyear)));

console.log(results);

.as-console-wrapper { max-height: 100% !important; top: 0; }

你如何比较 JS 中的 "week-year" 值？

How can you compare "week-year" value in JS?

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