excel 无法打开 Apache POI 加密的 xlsx
Apache POI encrypted xlsx cannot be opened in excel
我正在尝试使用 Apache POI 创建一个加密的 xlsx 文件。这是我的代码,运行良好:
public static void Encrypt(String data) throws IOException, GeneralSecurityException, InvalidFormatException {
Workbook wb = new XSSFWorkbook();
Sheet sheet1 = wb.createSheet("sheet1");
sheet1.createRow(0).createCell(0).setCellValue(data);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
wb.write(bos);
bos.close();
POIFSFileSystem fs = new POIFSFileSystem();
EncryptionInfo info = new EncryptionInfo(EncryptionMode.agile, CipherAlgorithm.aes256, HashAlgorithm.sha512, 256, 16, ChainingMode.cbc);
Encryptor enc = info.getEncryptor();
enc.confirmPassword("pass");
OPCPackage opc = OPCPackage.open(new ByteArrayInputStream(bos.toByteArray()));
OutputStream os = enc.getDataStream(fs);
opc.save(os);
opc.close();
FileOutputStream fos = new FileOutputStream("provawrite.xlsx");
fs.writeFilesystem(fos);
fos.close();
}
问题是当我打开生成的文件时,excel 一直抱怨文件已损坏。
我还尝试使用不同的加密模式更改 EncryptionInfo
实例化,但没有任何变化。
有人可以给我提示吗?!?
在写出文件系统之前必须关闭加密的输出流。在你的情况下,它在 opc.save(os);
.
之后缺少 os.close();
但为什么要绕行ByteArrayOutputStream
呢?
以下对我有效:
import java.io.*;
import org.apache.poi.poifs.filesystem.*;
import org.apache.poi.poifs.crypt.*;
import org.apache.poi.ss.usermodel.*;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class XSSFEncryption {
public static void doEncrypt(String data) throws Exception {
POIFSFileSystem fs = new POIFSFileSystem();
EncryptionInfo info = new EncryptionInfo(EncryptionMode.agile);
Encryptor enc = info.getEncryptor();
enc.confirmPassword("pass");
Workbook workbook = new XSSFWorkbook();
Sheet sheet = workbook.createSheet("sheet1");
sheet.createRow(0).createCell(0).setCellValue(data);
// write the workbook into the encrypted OutputStream
OutputStream encos = enc.getDataStream(fs);
workbook.write(encos);
workbook.close();
encos.close(); // this is necessary before writing out the FileSystem
OutputStream os = new FileOutputStream("provawrite.xlsx");
fs.writeFilesystem(os);
os.close();
fs.close();
}
public static void main(String[] args) throws Exception {
doEncrypt("Test");
}
}
我正在尝试使用 Apache POI 创建一个加密的 xlsx 文件。这是我的代码,运行良好:
public static void Encrypt(String data) throws IOException, GeneralSecurityException, InvalidFormatException {
Workbook wb = new XSSFWorkbook();
Sheet sheet1 = wb.createSheet("sheet1");
sheet1.createRow(0).createCell(0).setCellValue(data);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
wb.write(bos);
bos.close();
POIFSFileSystem fs = new POIFSFileSystem();
EncryptionInfo info = new EncryptionInfo(EncryptionMode.agile, CipherAlgorithm.aes256, HashAlgorithm.sha512, 256, 16, ChainingMode.cbc);
Encryptor enc = info.getEncryptor();
enc.confirmPassword("pass");
OPCPackage opc = OPCPackage.open(new ByteArrayInputStream(bos.toByteArray()));
OutputStream os = enc.getDataStream(fs);
opc.save(os);
opc.close();
FileOutputStream fos = new FileOutputStream("provawrite.xlsx");
fs.writeFilesystem(fos);
fos.close();
}
问题是当我打开生成的文件时,excel 一直抱怨文件已损坏。
我还尝试使用不同的加密模式更改 EncryptionInfo
实例化,但没有任何变化。
有人可以给我提示吗?!?
在写出文件系统之前必须关闭加密的输出流。在你的情况下,它在 opc.save(os);
.
os.close();
但为什么要绕行ByteArrayOutputStream
呢?
以下对我有效:
import java.io.*;
import org.apache.poi.poifs.filesystem.*;
import org.apache.poi.poifs.crypt.*;
import org.apache.poi.ss.usermodel.*;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class XSSFEncryption {
public static void doEncrypt(String data) throws Exception {
POIFSFileSystem fs = new POIFSFileSystem();
EncryptionInfo info = new EncryptionInfo(EncryptionMode.agile);
Encryptor enc = info.getEncryptor();
enc.confirmPassword("pass");
Workbook workbook = new XSSFWorkbook();
Sheet sheet = workbook.createSheet("sheet1");
sheet.createRow(0).createCell(0).setCellValue(data);
// write the workbook into the encrypted OutputStream
OutputStream encos = enc.getDataStream(fs);
workbook.write(encos);
workbook.close();
encos.close(); // this is necessary before writing out the FileSystem
OutputStream os = new FileOutputStream("provawrite.xlsx");
fs.writeFilesystem(os);
os.close();
fs.close();
}
public static void main(String[] args) throws Exception {
doEncrypt("Test");
}
}