正在重新分配的指针未分配

Question

我正在尝试动态分配结构数组，但每当我运行程序时，我都会收到：a.out(6487,0x7fff7ecb8300) malloc: * 对象错误0x7fff6f670000: 重新分配的指针未分配 * 在 malloc_error_break 设置断点调试

struct node {
    char course[25];
    char category[20];
    char prereq[50];
    char notes[50];
};



int main(int argc, char* argv[])
{
    FILE *fp;
    char *filename = argv[1];
    char *token;

    char buffer[100];
    char *del = ",\n";
    int num = 5, i = 0, j =0, count = 0;
    struct node *d = malloc(num * sizeof(struct node));
    char** complete = malloc(num * sizeof(char*));
    printf("%s\n", filename);


    if( (fp = fopen(filename, "r")) == NULL )
    {
        printf("unable to open %s\n", filename);
        exit(1);
    }
    while(fgets(buffer, sizeof(buffer), fp) != NULL)
    {

        if(count == num)
        {
            num = num + 5;
            struct node *d = realloc(d, sizeof(d)*num);
            printf("Reallocating\n");
        }  
        token = strtok(buffer, del);

        if(strncmp(token, "#", 1) != 0)
        {   

            strcpy(d[count].course, token);
            printf("%s\n", d[count].course);
            strcpy(d[count].category, strtok(NULL, del));
            printf("%s\n", d[count].category);
            strcpy(d[count].prereq, strtok(NULL, del));
            printf("%s\n", d[count].prereq);
            strcpy(d[count].notes, strtok(NULL, del));
            printf("%s\n", d[count].notes);
            count++;
        }


    }

Answer 1

在：

struct node *d = realloc(d, sizeof(d)*num);

这声明了一个新变量 d，其初始值未确定并将其传递给 realloc。将其更改为：

struct node *tmp = realloc(d, sizeof(*d)*num);
if(!tmp)
    ; // handle error
d = tmp;

Answer 2

struct node *d = realloc(d, sizeof(d)*num);

您正在声明一个新的 d 变量，它覆盖了前一个变量，并将其尚未初始化的值提供给 realloc。

您需要这样做：

struct node *newD = realloc(d, num * sizeof *d);
if(!newD) {
    // Allocation failure, do something about it and break out
} /* else */
d = newD;

另请注意，我更正了 sizeof，它测量的是指针的大小，而不是指针的大小。

正在重新分配的指针未分配

pointer being realloced was not allocated

c

malloc

realloc