PHP 准备好的语句处理重复条目

Question

我有一个问题，我无法使用准备好的语句处理重复条目。

我想在出现重复条目时结束程序。这就是我一直在努力做的事情：

function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){


    $conn = connection();

    $stmt = $conn->prepare("INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
                           VALUES (?, ?, ?, ?, ?)");




    $stmt->bind_param("sssis", $CVE, $Description, $Date, $Score, $Type);

    if ( false === $stmt ) {

       die('prepare() failed: ' . htmlspecialchars($mysqli->error));

    }


    $stmt->execute();

    $conn->close();


}

当不使用准备好的语句时，我以这种方式处理错误并且一切正常：

function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){


    $conn = connection();

    $Description = htmlspecialchars($Description);



    $sql = "INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
    VALUES ('".$CVE."', '".$Description."', '".$Date."', '".$Score."', '".$Type."')";

    if ($conn->query($sql) === TRUE) {
        //echo "New record created successfully";
    } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
        $conn->close();
        die();

    }

    $conn->close();

}

那么如何使用准备好的语句获得相同的结果？

提前致谢。

Answer 1

您可以在 $stmt->execute() 中连接检查以查看准备好的语句是否正常工作。

function insert_vulnerability ($CVE, $Description, $Date, $Score, $Type){
    $conn = connection();

    $stmt = $conn->prepare('
        INSERT INTO Vulnerabilities (CVE, Description, Date, Score, Type)
        VALUES (?, ?, ?, ?, ?)
    ');

    $stmt->bind_param('sssis', $CVE, $Description, $Date, $Score, $Type);
    if($stmt->execute()) { // true, success, else error
        echo 'New record created successfully';
    } else {
        echo $conn->error;
    }

    $conn->close();
}

请注意，您的准备语句端有一个未定义的变量：

$mysqli->error

PHP 准备好的语句处理重复条目

PHP Prepared Statements handle duplicate entry

php

mysql

error-handling

mysqli

prepared-statement