flask_mongo_engine 如何按 create_time desc 对顺序进行分页？

Question

class Session(db.DynamicDocument):
    title = db.StringField(required=False)
    created = db.FloatField(required=True)
    source = db.StringField()

@app.route('/page/<int:page>')
def sessions(page):
    return jsonify(Session.objects.paginate(page=page, per_page=5).items)

返回的是字典列表，默认为ASC，第一页包含最早的文档。

那么如何获取desc订单结果呢？

Answer 1

只需在 paginate() 之前添加 order_by()。

keys may be prefixed with + or - to determine the ordering direction

举个例子：

class Session(db.DynamicDocument):
    create_time = db.DateTimeField(required=True)

# clean before test
for i in Session.objects.all():
    i.delete()

for i in range(20):
    create_time = datetime.now()
    create_time = create_time.replace(year=2000 + i)
    ses = Session(create_time=create_time)
    ses.save()

print('2000 -> 2009')
items = Session.objects.order_by('create_time').paginate(page=1, per_page=10).items
for i in items:
    print(i.create_time)

print('2019 -> 2010')
items = Session.objects.order_by('-create_time').paginate(page=1, per_page=10).items
for i in items:
    print(i.create_time)

希望对您有所帮助。

flask_mongo_engine 如何按 create_time desc 对顺序进行分页？

flask_mongo_engine how to paginate order by create_time desc?

mongodb

flask

flask-mongoengine