TypeError: init() missing 1 required positional argument: 'id'

Question

我的意图是从 url 获取 int:id 并将数据从 init 函数存储到 self.user。它适用于除 init 之外的其他函数。有什么我需要补充的吗？还是不可能？

@api.resource('/api/users/<int:id>', endpoint='user')
class UserAPI(Resource):
    def __init__(self, id):
        self.user = User.query.get(id)
        self.reqparse = reqparse.RequestParser()
        self.reqparse.add_argument('username', type=str,
            help='No Name Provided', location='json')
        self.reqparse.add_argument('email', type=str,
            help='No Email Provided', location='json')
        self.reqparse.add_argument('password',type=str,
            help='No Password Provided', location="json")
        super(UserAPI, self).__init__()

错误日志如下：

Traceback (most recent call last):
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask_restful\__init__.py", line 265, in error_router
    return original_handler(e)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\_compat.py", line 32, in reraise
    raise value.with_traceback(tb)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask_restful\__init__.py", line 265, in error_router
    return original_handler(e)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\_compat.py", line 32, in reraise
    raise value.with_traceback(tb)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask_debugtoolbar\__init__.py", line 124, in dispatch_request
    return view_func(**req.view_args)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask_restful\__init__.py", line 446, in wrapper
    resp = resource(*args, **kwargs)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask_httpauth.py", line 61, in decorated
    return f(*args, **kwargs)
  File "C:\Users\kw\Envs\nektime\lib\site-packages\flask\views.py", line 83, in view
    self = view.view_class(*class_args, **class_kwargs)
TypeError: __init__() missing 1 required positional argument: 'id'

Answer 1

我认为这不可能。由于 Resource 不会与 id 等其他参数显式 init。如果你查看 flask-restful 和 flask 本身的代码，你会发现 Resource 有点像抽象的 class，其功能主要取决于 classmethod.

对了，RESTful的意思是Representational State Transfer，应该是stateless。也就是说，不同的请求之间不应该有任何不同的上下文。让资源记住用户违反了RESTfulAPI.

的设计原则

TypeError: __init__() missing 1 required positional argument: 'id'

TypeError: __init__() missing 1 required positional argument: 'id'

python

flask

flask-restful

TypeError: init() missing 1 required positional argument: 'id'

TypeError: init() missing 1 required positional argument: 'id'