shutil copyfile 在我的目标文件夹中给出 Errno 2

shutil copyfile giving Errno 2 on my destination folder

我写了如下函数:

def separate_files(filetree_list, destination):

    from shutil import copyfile
    from os import makedirs
    from os.path import join, exists, commonprefix
    
    try:
        for file in filetree_list:
            dst = join(destination,
                       '\'.join(file.split(commonprefix(filetree_list))[1].split('\')[0:-1]))
            if not exists(dst):
                print(dst, " doesn`t exist. Creating...")
                makedirs(dst)
                print(exists(dst), ". Path created.")
            print(file)
            copyfile(file, dst)
    except:
        print("Moving files has FAILED.")
    else:
        print("Moving files was SUCCESSFUL.")

当我用一个“filetree_list”列表调用它时,该列表包含单个元素和用 os.path.join 准备的目标:

filetree_list = ['C:\Users\<username>\staging_folder\folder_1\filename.xlsx'] 
destination = os.path.join(staging_dir, 'Sorted', 'Unwanted_files')

我收到以下错误:

---------------------------------------------------------------------------
FileNotFoundError                         Traceback (most recent call last)
<ipython-input-29-c3525a60c859> in <module>()
     14         print(exists(dst), ". Path created.")
     15     print(file)
---> 16     copyfile(file, dst)

    C:\ProgramData\Anaconda3\lib\shutil.py in copyfile(src, dst, follow_symlinks)
    119     else:
    120         with open(src, 'rb') as fsrc:
--> 121             with open(dst, 'wb') as fdst:
    122                 copyfileobj(fsrc, fdst)
    123     return dst

FileNotFoundError: [Errno 2] No such file or directory: 'C:\Users\<username>\staging_folder\Sorted\Unwanted_files\'

奇怪的是(此刻让我发疯),这个文件夹确实存在,并且是由 separate_files 中的“if not exists(dst)”块创建的功能 - 我什至可以在 Windows 资源管理器中看到它!

雪上加霜的是,当我 运行 这个函数使用相同的目标参数但列表中有多个字符串时,它执行了我期望的操作并且没有错误!

任何人都可以深入了解我在这里做错了什么吗?

https://docs.python.org/3/library/shutil.html#shutil.copyfile:

shutil.<b>copyfile</b>(<i>src</i>, <i>dst</i>, <i>*</i>, <i>follow_symlinks=True</i>)

Copy the contents (no metadata) of the file named src to a file named dst and return dst. src and dst are path names given as strings. dst must be the complete target file name; look at shutil.copy() for a copy that accepts a target directory path.

您正在尝试将目录作为 dst 传递给 copyfile。那是行不通的。