如何将数据框中的每一列拆分为两列?
How to split each of the columns in a data frame to two column?
我有一个这样的数据框(4 行 5 列):
Marker ind1 ind2 ind3 ind4
mark1 CT TT CT TT
mark2 AG AA AG AA
mark3 AC AA AC AA
mark4 CT TT CT TT
我想要做的是将每一列(第一列除外)拆分为两列。所以输出应该是这样的(4 行和 9 列):
Marker ind1 ind1 ind2 ind2 ind3 ind3 ind4 ind4
mark1 C T T T C T T T
mark2 A G A A A G A A
mark3 A C A A A C A A
mark4 C T T T C T T T
我知道如何拆分一栏
do.call(rbind,strsplit(test$JRP4RA6119.039, ""))
这给出了这个:
[,1] [,2]
[1,] "C" "T"
[2,] "A" "G"
[3,] "A" "C"
[4,] "C" "T"
我想要的是能够循环它并为一个数据帧中的所有列制作它。
提前致谢。
感觉有点牵强但是:
test_split <- data.frame(Marker=test$Marker,
do.call("cbind", lapply(apply(test[, -1], 2, strsplit, ""),
function(x) do.call("rbind", x))),
stringsAsFactors=F)
colnames(test_split)[-1] <- paste(rep(colnames(test)[-1], e=2), 1:2, sep="_")
test_split
# Marker JRP4RA6119.039_1 JRP4RA6119.039_2 JRP4RA6124.029_1 JRP4RA6124.029_2 JRP4RA6133.051_1 JRP4RA6133.051_2 JRP4RA6125.009_1 JRP4RA6125.009_2
#1 s7e4419xxx C T T T C T T T
#2 s7e7001s01 A G A A A G A A
#3 s7e3049xxx A C A A A C A A
#4 s7e4727xxx C T T T C T T T
> b <- as.data.frame(a[, 1])
> b[, 2] <- substr(a[, 2], 1, 1)
> b[, 3] <- substr(a[, 2], 2, 2)
> b[, 4] <- substr(a[, 3], 1, 1)
> b[, 5] <- substr(a[, 3], 2, 2)
> b[, 6] <- substr(a[, 4], 1, 1)
> b[, 7] <- substr(a[, 4], 2, 2)
> b[, 8] <- substr(a[, 5], 1, 1)
> b[, 9] <- substr(a[, 5], 2, 2)
> head(b)
a[, 1] V2 V3 V4 V5 V6 V7 V8 V9
1 mark1 C T T T C T T T
2 mark2 A G A A A G A A
3 mark3 A C A A A C A A
4 mark4 C T T T C T T T
> dim(b)
[1] 4 9
> names(b) <- c("Marker", "ind1", "ind1","ind2", "ind2", "ind3", "ind3", "ind4", "ind4")
> head(b)
Marker ind1 ind1 ind2 ind2 ind3 ind3 ind4
1 mark1 C T T T C T T
2 mark2 A G A A A G A
3 mark3 A C A A A C A
4 mark4 C T T T C T T
ind4
1 T
2 A
3 A
4 T
>
您可以轻松地将它变成一个循环,但由于列数相对较少,我没有必要这么做。
要使其成为循环,只需将其设置为
for(i in 2:ncol(a)){
}
您也可以尝试从 splitstackshape
cSplit_f
library(splitstackshape)
df1[-1] <- lapply(df1[-1] , function(x)
gsub('(?<=\w)(?=\w)', ',', x, perl=TRUE))
cSplit_f(df1, 2:ncol(df1), sep=',')
# Marker ind1_1 ind1_2 ind2_1 ind2_2 ind3_1 ind3_2 ind4_1 ind4_2
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
或者按照@Ananda Mahto的建议,cSplit
在大型数据集上可能更高效,这个可以直接使用,无需更改分隔符。
cSplit(df1, names(df1)[-1], sep="", stripWhite = FALSE)
# Marker ind1_1 ind1_2 ind2_1 ind2_2 ind3_1 ind3_2 ind4_1 ind4_2
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
或使用 data.table
中的 tstrsplit
library(data.table)#v1.9.5+
setDT(df1)
cbind(Marker=df1$Marker,df1[, unlist(lapply(.SD, function(x)
tstrsplit(x, '')), recursive=FALSE), .SDcols=-1])
# Marker ind11 ind12 ind21 ind22 ind31 ind32 ind41 ind42
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
数据
df1 <- structure(list(Marker = c("mark1", "mark2", "mark3", "mark4"),
ind1 = c("CT", "AG", "AC", "CT"), ind2 = c("TT", "AA", "AA",
"TT"), ind3 = c("CT", "AG", "AC", "CT"), ind4 = c("TT", "AA",
"AA", "TT")), .Names = c("Marker", "ind1", "ind2", "ind3",
"ind4"), class = "data.frame", row.names = c(NA, -4L))
我有一个这样的数据框(4 行 5 列):
Marker ind1 ind2 ind3 ind4
mark1 CT TT CT TT
mark2 AG AA AG AA
mark3 AC AA AC AA
mark4 CT TT CT TT
我想要做的是将每一列(第一列除外)拆分为两列。所以输出应该是这样的(4 行和 9 列):
Marker ind1 ind1 ind2 ind2 ind3 ind3 ind4 ind4
mark1 C T T T C T T T
mark2 A G A A A G A A
mark3 A C A A A C A A
mark4 C T T T C T T T
我知道如何拆分一栏
do.call(rbind,strsplit(test$JRP4RA6119.039, ""))
这给出了这个:
[,1] [,2]
[1,] "C" "T"
[2,] "A" "G"
[3,] "A" "C"
[4,] "C" "T"
我想要的是能够循环它并为一个数据帧中的所有列制作它。
提前致谢。
感觉有点牵强但是:
test_split <- data.frame(Marker=test$Marker,
do.call("cbind", lapply(apply(test[, -1], 2, strsplit, ""),
function(x) do.call("rbind", x))),
stringsAsFactors=F)
colnames(test_split)[-1] <- paste(rep(colnames(test)[-1], e=2), 1:2, sep="_")
test_split
# Marker JRP4RA6119.039_1 JRP4RA6119.039_2 JRP4RA6124.029_1 JRP4RA6124.029_2 JRP4RA6133.051_1 JRP4RA6133.051_2 JRP4RA6125.009_1 JRP4RA6125.009_2
#1 s7e4419xxx C T T T C T T T
#2 s7e7001s01 A G A A A G A A
#3 s7e3049xxx A C A A A C A A
#4 s7e4727xxx C T T T C T T T
> b <- as.data.frame(a[, 1])
> b[, 2] <- substr(a[, 2], 1, 1)
> b[, 3] <- substr(a[, 2], 2, 2)
> b[, 4] <- substr(a[, 3], 1, 1)
> b[, 5] <- substr(a[, 3], 2, 2)
> b[, 6] <- substr(a[, 4], 1, 1)
> b[, 7] <- substr(a[, 4], 2, 2)
> b[, 8] <- substr(a[, 5], 1, 1)
> b[, 9] <- substr(a[, 5], 2, 2)
> head(b)
a[, 1] V2 V3 V4 V5 V6 V7 V8 V9
1 mark1 C T T T C T T T
2 mark2 A G A A A G A A
3 mark3 A C A A A C A A
4 mark4 C T T T C T T T
> dim(b)
[1] 4 9
> names(b) <- c("Marker", "ind1", "ind1","ind2", "ind2", "ind3", "ind3", "ind4", "ind4")
> head(b)
Marker ind1 ind1 ind2 ind2 ind3 ind3 ind4
1 mark1 C T T T C T T
2 mark2 A G A A A G A
3 mark3 A C A A A C A
4 mark4 C T T T C T T
ind4
1 T
2 A
3 A
4 T
>
您可以轻松地将它变成一个循环,但由于列数相对较少,我没有必要这么做。
要使其成为循环,只需将其设置为
for(i in 2:ncol(a)){
}
您也可以尝试从 splitstackshape
cSplit_f
library(splitstackshape)
df1[-1] <- lapply(df1[-1] , function(x)
gsub('(?<=\w)(?=\w)', ',', x, perl=TRUE))
cSplit_f(df1, 2:ncol(df1), sep=',')
# Marker ind1_1 ind1_2 ind2_1 ind2_2 ind3_1 ind3_2 ind4_1 ind4_2
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
或者按照@Ananda Mahto的建议,cSplit
在大型数据集上可能更高效,这个可以直接使用,无需更改分隔符。
cSplit(df1, names(df1)[-1], sep="", stripWhite = FALSE)
# Marker ind1_1 ind1_2 ind2_1 ind2_2 ind3_1 ind3_2 ind4_1 ind4_2
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
或使用 data.table
tstrsplit
library(data.table)#v1.9.5+
setDT(df1)
cbind(Marker=df1$Marker,df1[, unlist(lapply(.SD, function(x)
tstrsplit(x, '')), recursive=FALSE), .SDcols=-1])
# Marker ind11 ind12 ind21 ind22 ind31 ind32 ind41 ind42
#1: mark1 C T T T C T T T
#2: mark2 A G A A A G A A
#3: mark3 A C A A A C A A
#4: mark4 C T T T C T T T
数据
df1 <- structure(list(Marker = c("mark1", "mark2", "mark3", "mark4"),
ind1 = c("CT", "AG", "AC", "CT"), ind2 = c("TT", "AA", "AA",
"TT"), ind3 = c("CT", "AG", "AC", "CT"), ind4 = c("TT", "AA",
"AA", "TT")), .Names = c("Marker", "ind1", "ind2", "ind3",
"ind4"), class = "data.frame", row.names = c(NA, -4L))