Java：将单个数组除以一个对象元素值分成2个数组

Question

编辑。谢谢。

我有一组 'normal' 辆车和 'large' 辆车。我有一项任务要求我将它们分开以贡献更大的应用程序。一个数组用于大型车辆，一个数组用于包含每个元素的所有信息的普通车辆。不允许使用 ArrayList，因为我的讲师正在教我们基础知识。

阵列样本

27723 4/09/61 large 7337 28507 22-02-1983 large 7055 28558 1/05/70 normal 3518

//On button press
//recieve single item from array from main and test it
//array in main will be looped for all elements. 
public String loadVehicle(Vehicle v) {
String res = Constants.OK;

boolean normBool = false;
boolean largeBool = false;

//if both arrays are full , stop the method call in the main form
if (normBool && largeBool){return Constants.ERROR;}

//if vehicle size is normal, fill the normal veh array
if(v.getSize().equals(Constants.NORMAL_SIZE))
{
    for(int i = 0; i<normalVehicles.length; i++)
    {
        //if norm veh array element is null, add the appropriate value to it
        if(normalVehicles[i] == null){normalVehicles[i] = v;}

        else{normBool = true;}
    }
}
//if veh size is large put it in the large veh array
else if(v.getSize().equals(Constants.LARGE_SIZE))
{   
    for(int iL = 0; iL<largeVehicles.length; iL++)
    {
        if(largeVehicles[iL] == null){largeVehicles[iL] = v;}
        else{largeBool = true;}
    }
}

return res;
}//end method

Answer 1

你可以这样写你的循环：

for(int i = 0; i < normalVehicles.length; i++)
{
  if(normalVehicles[i] == null)
  {
    normalVehicles[i] = v;
    break;
  }
}
// if last slot isn't null then it's full
normBool = normalVehicles[normalVehicles.length-1] != null;

Answer 2

似乎你不能使用内置的 LinkedList class，那么这样做：

在您的载具中添加以下代码class：

class Vehicle(){

     //YOUR OTHER PIECES OF CODES ...

     private static Vehicle firstLargeVehicle;
     private Vehicle nextLargeVehicle;
     private int index;

     public void setIndex(int index){
          this.index = index;
          if(index == 0) Vehicle.firstLargeVehicle = this;
     }

     public int getIndex(){
          return index;
     }

     public void setNextLargeVehicle(Vehicle nextLargeVehicle){
          this.nextLargeVehicle = nextLargeVehicle;
     }

     public Vehicle getNextLargeVehicle(){
          return nextLargeVehicle;
     }

     public addLargeVehicle(Vehicle newVehicle){
          this.nextLargeVehicle = newVehicle;
          newVehicle.setIndex(index + 1);
     }

     public getListSize(){
          Vehicle lastOne = this;
          while (lastOne.getNextLargeVehicle() != null){
              lastOne = lastOne.getNextLargeVehicle();
          }

          return lastOne.getIndex() + 1;
     }

     public static Vehicle[] largeVehiclesToArray(){
          Vehicle[] result = new Vehicle[firstLargeVehicle.getListSize()]();
          Vehicle pointer = firstLargeVehicle;
          for (int counter = 0; pointer != null; counter ++){
              result[counter] = pointer;
              pointer = pointer.getNextLargeVehicle();
          }

          return result;
     }

 }

然后在您的主循环中，执行类似于以下代码的操作：

  Vehicle vehicle = null; 
  for(Vehicle newVehicle : allVehicles) {
       if (newVehicle.isLarge()){
            if (vehicle == null) {
                 vehicle = newVehicle;
                 vehicle.setIndex(0);
            }else{
                 vehicle.addLargeVehicle(newVehicle));
            }
       } 
  } 

  Vehicle[] largeVehicles = Vehicle.largeVehiclesToArray();

普通车辆也是如此。有什么问题吗？

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