Flask-PyMongo

Question

我正在尝试使用 flask-py 初始化我的数据库mongo。

但是我得到以下错误，

File "run.py", line 22, in
app = create_app("config")
File "run.py", line 11, in create_app
mongo.init_app(app)
TypeError: init_app() missing 1 required positional argument: 'app'

run.py

from flask import Flask
from app import api_bp
from db import mongo

def create_app(config_filename):

    app = Flask(__name__)
    app.config.from_object(config_filename)
    app.register_blueprint(api_bp, url_prefix='/api')

    mongo.init_app(app)

    return app

# def logger():


# def database():


if __name__ == "__main__":
    app = create_app("config")
    app.run(host='0.0.0.0', port=8080, debug=True)

db.py

from flask_pymongo import PyMongo

mongo = PyMongo

config.py

DEBUG = True
SECRET_KEY = "secret"
MONGO_URI = "mongodb://localhost:27017/api"

app/__init__.py

import os
import json
import datetime
from flask import Blueprint
from flask import jsonify
from flask_restful import Api
from .users.resource import UsersResource

api_bp = Blueprint('api', __name__)
api = Api(api_bp)


api.add_resource(UsersResource, '/users')

app/users/resource.py

我想让他们将 mongo 导入此资源，以便我可以访问用户集合。

from flask_restful import Resource
from flask import jsonify
from .repository import UsersRepository

class UsersResource(Resource):

    def __init__(self):

        self.repository = UsersRepository()

    def get(self):

        data = {"Users": "Resource"}
        res = data, 200
        return res

我正在尝试使用 Flask-restful 和 flask-pymongo 使用资源设置 restful api。欢迎任何其他改进我的方法的建议。

Answer 1

您没有在 db.py 中实例化 PyMongo class。

mongo = PyMongo()

Answer 2

你应该像 this:

这样使用 flask-pymongo

from flask import Flask
from flask_pymongo import PyMongo

app = Flask(__name__)
app.config["MONGO_URI"] = "mongodb://localhost:27017/myDatabase"
mongo = PyMongo(app)

因此在 run.py 中，您应该使用此代码：

from flask import Flask
from app import api_bp
from db import mongo

def create_app(config_filename):

    app = Flask(__name__)
    app.config.from_object(config_filename)
    app.register_blueprint(api_bp, url_prefix='/api')

    # mongo.init_app(app) # remove this line

    return app

# def logger():


# def database():


if __name__ == "__main__":
    app = create_app("config")
    py_mongo = mongo(app)
    app.run(host='0.0.0.0', port=8080, debug=True)

Flask-PyMongo - init_app() 缺少 1 个必需的位置参数：'app'

Flask-PyMongo - init_app() missing 1 required positional argument: 'app'

python

pymongo

flask

flask-restful