Bash : 如何在连续循环中拖尾最新文件

Question

我正在尝试编写脚本来监视日志文件，并在出现特定错误时执行特定功能。我的主要代码可以正常工作，但遇到一个问题。应用程序在系统日期更改时创建新的日志文件（日志文件名称模式为 LOG.NODE1.DDMMYYYY），如何让我的代码自动切换到创建的新文件。到目前为止，以下是我的脚本，

#!/bin/sh

logfile=$(ls -t $DIR"/env/log/LOG"* | head -n 1)
echo $logfile
tail -f $logfile | while read LOGLINE
do

if [[  "${LOGLINE}" == *";A database exception has occurred: FATAL DBERR:  SQL_ERROR: ORA-00001: unique constraint (IX_TEST1) violated"* ]];

then
        #Do something

fi
done

Answer 1

#!/bin/bash
#      ^^^^ -- **NOT** /bin/sh

substring=";A database exception has occurred: FATAL DBERR:  SQL_ERROR: ORA-00001: unique constraint (IX_TEST1) violated"
newest=
timeout=10  # number of seconds of no input after which to look for a newer file

# sets a global shell variable called "newest" when run
# to keep overhead down, this avoids invoking any external commands
find_newest() {
  set -- "${DIR?The variable DIR is required}"/env/log/LOG*
  [[ -e  || -L  ]] || return 1
  newest=; shift
  while (( $# )); do
    [[  -nt $newest ]] && newest=
    shift
  done
}

while :; do
  find_newest  # check for newer files
  # if the newest file isn't the one we're already following...
  if [[ $tailing_from_file != "$newest" ]]; then
    exec < <(tail -f -- "$newest")  # start a new copy of tail following the newer one
    tailing_from_file=$newest       # and record that file's name
  fi
  if read -t "$timeout" -r line && [[ $line = *"$substring"* ]]; then
    echo "Do something here"
  fi
done

Bash : 如何在连续循环中拖尾最新文件

Bash : How to tail latest file in continuous loop

bash

tail

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