fos 创建用户 Symfony
fos create user Symfony
所以我正在与 fosuser 合作!
我设法在 class
中添加了一些字段
<?php
namespace mynamespace;
use FOS\UserBundle\Model\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;
class Person extends BaseUser
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @var string
*
* @ORM\Column(name="about", type="string", length=255,nullable=true)
*/
private $about;
// Change the targetEntity path if you want to create the group
/**
* @ORM\ManyToMany(targetEntity="userBundle\Entity\Group")
* @ORM\JoinTable(name="fos_user_user_group",
* joinColumns={@ORM\JoinColumn(name="user_id", referencedColumnName="id")},
* inverseJoinColumns={@ORM\JoinColumn(name="group_id", referencedColumnName="id")}
* )
*/
protected $groups;
public function __construct()
{
parent::__construct();
// your own logic
}
/**
* Get about
*
* @return String
*/
public function getAbout()
{
return $this->about;
}
/**
* Set about
*
* @param String $about
* @return User
*/
public function setAbout($about)
{
$this->about = $about;
return $this;
}
}
之后,我使用以下命令更新了数据库的架构
php bin/console doctrine:schema:update --force
问题是当我尝试使用命令行创建 fos:user 时出现此错误
An exception occurred while executing 'INSERT INTO fos_user (username, username_canonical, email, email_canonical, enabled, salt, password, last_login, confirmation_token, passw
ord_requested_at, roles, about) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
而且我无法手动将值插入数据库,因为某些字段已加密,例如密码
我可以做什么来更新 fos:user:create
命令以便我可以填写 "about" 字段
谢谢
在您的构造中设置一个默认值,以便在插入数据库时没有空值:
public function __construct()
{
parent::__construct();
$this->about = "default about value"; //<-- add this
// your own logic
}
所以我正在与 fosuser 合作! 我设法在 class
中添加了一些字段<?php
namespace mynamespace;
use FOS\UserBundle\Model\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;
class Person extends BaseUser
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @var string
*
* @ORM\Column(name="about", type="string", length=255,nullable=true)
*/
private $about;
// Change the targetEntity path if you want to create the group
/**
* @ORM\ManyToMany(targetEntity="userBundle\Entity\Group")
* @ORM\JoinTable(name="fos_user_user_group",
* joinColumns={@ORM\JoinColumn(name="user_id", referencedColumnName="id")},
* inverseJoinColumns={@ORM\JoinColumn(name="group_id", referencedColumnName="id")}
* )
*/
protected $groups;
public function __construct()
{
parent::__construct();
// your own logic
}
/**
* Get about
*
* @return String
*/
public function getAbout()
{
return $this->about;
}
/**
* Set about
*
* @param String $about
* @return User
*/
public function setAbout($about)
{
$this->about = $about;
return $this;
}
}
之后,我使用以下命令更新了数据库的架构
php bin/console doctrine:schema:update --force
问题是当我尝试使用命令行创建 fos:user 时出现此错误
An exception occurred while executing 'INSERT INTO fos_user (username, username_canonical, email, email_canonical, enabled, salt, password, last_login, confirmation_token, passw
ord_requested_at, roles, about) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
而且我无法手动将值插入数据库,因为某些字段已加密,例如密码
我可以做什么来更新 fos:user:create
命令以便我可以填写 "about" 字段
谢谢
在您的构造中设置一个默认值,以便在插入数据库时没有空值:
public function __construct()
{
parent::__construct();
$this->about = "default about value"; //<-- add this
// your own logic
}