如何用这段代码实现下一个和上一个按钮?

How to implement next and previous button with this code?

我的代码有一个开关实现来实现所需的输出。现在我需要这个实现也有下一个和上一个按钮。但我不知道简单的解决方案,为此起步。这是我的代码:

   private MediaPlayer clipSetup(int i){
    switch (i){
        case 1:
            mediaPlayer = MediaPlayer.create(this, R.raw.al01);
            mediaPlayer.start(); 
            break;
        case 2:
            mediaPlayer = MediaPlayer.create(this, R.raw.al02);
            mediaPlayer.start();    
            break;
        case 3:
            mediaPlayer = MediaPlayer.create(this, R.raw.al02);
            mediaPlayer.start();
            break;
        }
        return mediaPlayer;
     }

现在查看这段代码,我希望实现 OnClick 按钮。

希望对您有所帮助。

int current=0;
@Override
public void onClick(View v) {
    switch (v.getId()){
        case R.id.btn_back:
            current++;
            break;
        case R.id.btn_next:
            if(current<=0)
                current=2;
            else
            current--;
            break;
    }
    clipSetup(current%3+1);
}

如果您需要实现远程按钮,请使用下面的代码。

        int keycode = event.getKeyCode();

        if(event.getAction() != KeyEvent.ACTION_DOWN){
            return true;
        }

            switch (keycode){
                case KeyEvent.KEYCODE_DPAD_LEFT :
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            rewindSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_DPAD_RIGHT:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            fastForwardSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_DPAD_UP:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            showSurfaceControls();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_DPAD_DOWN:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            if(!vidPaused){
                                pauseSurfacePlayer();
                            }else {
                                playSurfacePlayer();
                            }
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_PROG_RED://rewind
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            rewindSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_PROG_GREEN://forward
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            fastForwardSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_PLAY_PAUSE:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            if(!vidPaused){
                                pauseSurfacePlayer();
                            }else {
                                playSurfacePlayer();
                            }
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_STOP:
                    stopVideo();
                    break;
                case 23://play/pause
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            if(!vidPaused){
                                pauseSurfacePlayer();
                            }else {
                                playSurfacePlayer();
                            }
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_FAST_FORWARD:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            fastForwardSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_REWIND:
                    if(videoType.equals(GENERAL)){
                        if(event.getAction() == KeyEvent.ACTION_DOWN){
                            rewindSurfacePlayer();
                        }
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_PAUSE:
                    if(event.getAction() == KeyEvent.ACTION_DOWN){
                        pauseSurfacePlayer();
                    }
                    break;
                case KeyEvent.KEYCODE_MEDIA_PLAY:
                    if(event.getAction() == KeyEvent.ACTION_DOWN){
                        playSurfacePlayer();
                    }
                    break;
            }

顺便说一句,这需要继续执行 dispatchKeyEvent 方法。你也可以在那里做后退按钮的句柄。无需使用 onBackPressed 方法。如果您已经在使用 onBackPressed 并想使用 dispatchKeyEvent,请删除您的 onBackPressed 方法。