在新的虚拟主机上出现此错误未定义的偏移量:1 和 2
Getting this error on new webhost Undefined offset: 1 and 2
我最近将我的脚本移到了一个新的虚拟主机中,现在我收到了这个错误
注意:未定义的偏移量:1($id2 的行)
注意:未定义的偏移量:2($id3 行)
这是我的 PHP 代码
<?php
include '../connect_database.php';
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
$rows[] = $row;
$id1= $rows[0]['score'];
$id2= $rows[1]['score'];
$id3= $rows[2]['score'];
}
$list['scores'] = array('data' => $id1, 'data1' => $id2, 'data2' => $id3);
$myJSON = json_encode($list);
echo $myJSON;
print_r($rows);
?>
知道为什么吗?
我认为这是设计缺陷的表现。看起来您正在尝试查找 3 位玩家的分数。您正在遍历 3 行,但试图在每次迭代中访问所有 3 名玩家的数据。您应该改为在各自的迭代中访问每个玩家的数据,并建立一个玩家数据列表。
为了直接回答您的问题,在迭代 1 中您尝试访问元素 0、1 和 2,但 $rows
仅填充了 0。
+-----------+-------------------------+--------------------------+
| Iteration | You're trying to access | You only have access to |
+-----------+-------------------------+--------------------------+
| 1 | 0,1,2 | 0 |
| 2 | 0,1,2 | 0,1 |
| 3 | 0,1,2 | 0,1,2 |
+-----------+-------------------------+--------------------------+
示例
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
// You only have access to a single $row here.
// Build up an array of the data you want instead of tring to access "other rows"
$scores[] = $row['score'];
}
// Now, you can use $scores to build $list... or build $list inside the loop.
?>
编辑
Do you mind to show me example how to assign the array results to
something like this? $list['scores'] = array('data' => $id1, 'data1'
=> $id2, 'data2' => $id3);
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$counter = 0;
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
$keyName = 'data';
if ($counter > 0) {
$keyName = 'data' . $counter;
}
$scores[$keyName] = $row['score'];
$counter++;
}
$list['scores'] = $scores;
echo json_encode($list);
我最近将我的脚本移到了一个新的虚拟主机中,现在我收到了这个错误
注意:未定义的偏移量:1($id2 的行) 注意:未定义的偏移量:2($id3 行)
这是我的 PHP 代码
<?php
include '../connect_database.php';
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
$rows[] = $row;
$id1= $rows[0]['score'];
$id2= $rows[1]['score'];
$id3= $rows[2]['score'];
}
$list['scores'] = array('data' => $id1, 'data1' => $id2, 'data2' => $id3);
$myJSON = json_encode($list);
echo $myJSON;
print_r($rows);
?>
知道为什么吗?
我认为这是设计缺陷的表现。看起来您正在尝试查找 3 位玩家的分数。您正在遍历 3 行,但试图在每次迭代中访问所有 3 名玩家的数据。您应该改为在各自的迭代中访问每个玩家的数据,并建立一个玩家数据列表。
为了直接回答您的问题,在迭代 1 中您尝试访问元素 0、1 和 2,但 $rows
仅填充了 0。
+-----------+-------------------------+--------------------------+
| Iteration | You're trying to access | You only have access to |
+-----------+-------------------------+--------------------------+
| 1 | 0,1,2 | 0 |
| 2 | 0,1,2 | 0,1 |
| 3 | 0,1,2 | 0,1,2 |
+-----------+-------------------------+--------------------------+
示例
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
// You only have access to a single $row here.
// Build up an array of the data you want instead of tring to access "other rows"
$scores[] = $row['score'];
}
// Now, you can use $scores to build $list... or build $list inside the loop.
?>
编辑
Do you mind to show me example how to assign the array results to something like this? $list['scores'] = array('data' => $id1, 'data1' => $id2, 'data2' => $id3);
<?php
// Turn on error reporting
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
// Show MySQL errors as PHP exceptions
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
include '../connect_database.php';
// Build up this list inside the loop.
$scores = [];
$counter = 0;
$sql = "SELECT score FROM dailyscore Where Id IN (1,2,3)";
date_default_timezone_set('America/New_York');
$result = $connect->query($sql);
while ($row = mysqli_fetch_assoc($result)){
$keyName = 'data';
if ($counter > 0) {
$keyName = 'data' . $counter;
}
$scores[$keyName] = $row['score'];
$counter++;
}
$list['scores'] = $scores;
echo json_encode($list);