NodeJS 加密模块：干净的密码重用

Question

我对 Node.js 中的加密模块有点陌生。我写了一个加密函数，它工作得很好但看起来很糟糕。这个有更好的写法吗？

const encrypt = data => {
  const iv = crypto.randomBytes(16);
  const key = crypto.randomBytes(32).toString('hex').slice(0, 32);

  const cipher1 = crypto.createCipheriv(algorithm, new Buffer(key), iv);
  const cipher2 = crypto.createCipheriv(algorithm, new Buffer(key), iv);
  const cipher3 = crypto.createCipheriv(algorithm, new Buffer(key), iv);

  const encryptedFile = Buffer.concat([cipher1.update(data.file), cipher1.final()]);
  const encryptedFileName = Buffer.concat([cipher2.update(data.fileName), cipher2.final()]).toString('hex');
  const encryptedId = Buffer.concat([cipher3.update(data.Id), cipher3.final()]).toString('hex');

  return {
    file: encryptedFile,
    fileName: encryptedFileName,
    id: iv.toString('hex') + ':' + encryptedId.toString('hex'),
    key
  };
};

输入是这个结构的一个对象：

{
  file: <Buffer>,
  fileName: <String>,
  Id: <String>
}

我需要使用相同的密钥 + iv 加密所有值，但不是一次加密整个对象。有没有办法重构它以避免重复？

Answer 1

试试这个：

const encrypt = (data, key, iv) => {
    const cipher = crypto.createCipheriv(algorithm, new Buffer(key), iv);

    return Buffer.concat([cipher.update(data), cipher.final()]);
};

const encrypt = data => {
    const iv = crypto.randomBytes(16);
    const key = crypto
      .randomBytes(32)
      .toString('hex')
      .slice(0, 32);

    return {
      file: encrypt(data.file, key, iv),
      fileName: encrypt(data.fileName, key, iv).toString('hex'),
      id: `${iv.toString('hex')}:${encrypt(data.Id, key, iv).toString('hex')}`,
      key,
    };
  };

NodeJS 加密模块：干净的密码重用

NodeJS crypto module: clean cipher reuse

javascript

encryption

cryptography

node.js

cryptojs