更新 UIMenuController 中的菜单项

Updating Menu Items In UIMenuController

我想更新 tableview 菜单项控制器中的菜单项,因为现在我只得到这些

我已经实现了这个:

func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
        let forword = UIMenuItem(title: "Demo", action: #selector(self.demo))
        UIMenuController.shared.menuItems?.append(forword)
        UIMenuController.shared.update()
        return true
    }
    
    func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
        UIMenuController.shared.setMenuVisible(true, animated: true)
    }
    
    func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
        return true
    }
    
    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        self.clearAllSelectedCell()
    }

但我的要求是:

我怎样才能做到这一点?

您的代码有一些问题……

  • 不要使用UIMenuController.shared.menuItems?.append,直接设置menuItems
  • 不要在 shouldShowMenuForRowAt 中这样做,只在 viewDidLoad
  • 中这样做一次
  • 你不需要setMenuVisible

最重要的是

  • 菜单项的操作必须是 table 视图单元格子类上的方法。

所以,在你的情况下……

你的 table 视图控制器应该有这些方法…

override func viewDidLoad() {
    super.viewDidLoad()

    let forward = UIMenuItem(title: "Forward", action: #selector(MyCell.menuItemTapped(_ :)))
    let delete = UIMenuItem(title: "Delete", action: #selector(MyCell.menuItemTapped(_ :)))
    UIMenuController.shared.menuItems = [forward, delete]
    UIMenuController.shared.update()
}

override func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
    return true
}

override func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
}

override func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
    return true
}

你的手机应该有……

class MyCell: UITableViewCell {
    @objc func menuItemTapped(_ sender: UIMenuController) {
    }
}
1.  create protocol to provide control into your view controller :

public protocol MenuItemDelegate {
    func copyAction(cell: UITableViewCell)
    func forwordAction(cell: UITableViewCell)
    func deleteAction(cell: UITableViewCell)
}

2.  create a custom table cell:

        class MyTableCell: UITableViewCell {

            var menuItemDelegate: MenuItemDelegate!

            var isCopyEnable = true
            var isForwardEnable = true
            var isDeleteEnable = true


            override func awakeFromNib() {
                super.awakeFromNib()
            }

            func setUpmenu(){
                let menu = UIMenuController.shared
                let forword = UIMenuItem(title: "Forward", action: #selector(self.forword(_:)))
                let delete = UIMenuItem(title: "Delete", action: #selector(self.deleteAction(_:)))
                menu.menuItems = [forword,delete]
                if !isDeleteEnable{
                    menu.menuItems?.remove(at: (menu.menuItems?.index(of: delete))!)
                }
                if !isForwardEnable{
                    menu.menuItems?.remove(at: (menu.menuItems?.index(of: forword))!)
                }
                menu.update()
            }

            override public func copy(_ sender: Any?) {
                UIPasteboard.general.string = accessibilityValue
                menuItemDelegate.copyAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            @objc public func forword(_ sender: Any?) {
                menuItemDelegate.forwordAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            @objc public func deleteAction(_ sender: Any?) {
                menuItemDelegate.deleteAction(cell: self)
                UIMenuController.shared.setMenuVisible(false, animated: true)
            }

            override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
                return (action == #selector(copy(_:))  || action == #selector(forword(_:)) || action == #selector(deleteAction(_:)))
            }
    }

3. Implement in view controller as like : 


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "MyTableCell", for: indexPath) as! MyTableCell
    cell.isForwardEnable = false
    cell.setUpmenu()
    return cell
}

func tableView(_ tableView: UITableView, shouldShowMenuForRowAt indexPath: IndexPath) -> Bool {
    return true
}

func tableView(_ tableView: UITableView, performAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) {
    UIMenuController.shared.setMenuVisible(true, animated: true)
}

func tableView(_ tableView: UITableView, canPerformAction action: Selector, forRowAt indexPath: IndexPath, withSender sender: Any?) -> Bool {
    return true
}

它将帮助您实现这一目标。

按照以下步骤,实现长按自定义物品。

  1. 将下面的代码粘贴到 viewDidload 方法中 let reply = UIMenuItem(title: "Reply", action: #selector(MessageCollectionViewCell.reply(_ :))) 让编辑 = UIMenuItem(标题:"Edit",操作:#selector(MessageCollectionViewCell.edit(_ :))) let forward = UIMenuItem(title: "Forward", action: #selector(MessageCollectionViewCell.forward(_ :))) UIMenuController.shared.menuItems = [回复、编辑、转发] UIMenuController.shared.update()

  2. 自定义单元格的扩展 扩展 MessageCollectionViewCell {

    @objc func reply(_ sender: Any?) { // 获取集合视图 如果让 collectionView = self.superview 作为? UICollectionView { // 获取索引路径 如果让 indexPath = collectionView.indexPath(for: self) { // 触发动作 collectionView.delegate?.collectionView?(collectionView, performAction: #selector(MessageCollectionViewCell.reply(_:)), forItemAt: indexPath, withSender: 发件人) } } }

    @objc func edit(_ sender: Any?) { // 获取集合视图 如果让 collectionView = self.superview 作为? UICollectionView { // 获取索引路径 如果让 indexPath = collectionView.indexPath(for: self) { // 触发动作 collectionView.delegate?.collectionView?(collectionView, performAction: #selector(MessageCollectionViewCell.edit(_:)), forItemAt: indexPath, withSender: 发件人) } } }

    @objc func forward(_ sender: Any?) { // 获取集合视图 如果让 collectionView = self.superview 作为? UICollectionView { // 获取索引路径 如果让 indexPath = collectionView.indexPath(for: self) { // 触发动作 collectionView.delegate?.collectionView?(collectionView, performAction: #selector(MessageCollectionViewCell.forward(_:)), forItemAt: indexPath, withSender: 发件人) } } }

}

  1. 在您的控制器中添加此代码,在我的例子中这样做 (class ChatViewController: MessagesViewController{})

    // -------------------------------------- ------------------------------------------ // MARK: - 处理长按动作 // ---------------------------------------------- -------------------------------------- override func collectionView(_ collectionView: UICollectionView, shouldShowMenuForItemAt indexPath: IndexPath) -> Bool { return 真 }

    override func collectionView(_ collectionView: UICollectionView, canPerformAction action: Selector, forItemAt indexPath: IndexPath, withSender sender: Any?) -> Bool { 打印(action.description) 让消息 = 消息[indexPath.section] //let message = messagesDataSource.messageForItem(at: indexPath, in: messagesCollectionView)

    if action == NSSelectorFromString("reply:") {
        return true
    }
    else if action == NSSelectorFromString("edit:") {
        return true
    
    }
    else if action == NSSelectorFromString("forward:") {
        return true
    }
    else {
        return super.collectionView(collectionView, canPerformAction: action, forItemAt: indexPath, withSender: sender)
    }
    

    }

    override func collectionView(_ collectionView: UICollectionView, performAction action: Selector, forItemAt indexPath: IndexPath, withSender sender: Any?) {

    if action == NSSelectorFromString("reply:") {
        print("reply item here!!")
    }
    else if action == NSSelectorFromString("edit:") {
        print("edit item here!!")
    }
    else if action == NSSelectorFromString("forward:") {
        print("forward item here!!")
    }
    else {
        super.collectionView(collectionView, performAction: action, forItemAt: indexPath, withSender: sender)
    }
    

    }