给定一个索引位置，我如何拆分出该位置所在的句子？

Question

我正在使用 JavaScript，我的文字是：

Dana's places, we're having people coming to us people wanna buy condos. They want to move quickly and we're just losing out on a lot of great places. Really what would you say this?

如果我的索引位置是6，我只想得到第一句：Dana's places, we're having people coming to us people wanna buy condos.

如果我的索引位置是80，我只想得到第二句：They want to move quickly and we're just losing out on a lot of great places.

如何根据位置解析句子？

Answer 1

如果你分期。字符串对象有一个名为 split 的原型方法，returns 一个拆分字符串的数组。在下面的示例中，str 是一个保存字符串的变量。

const str = 'first sentence. Second sentence. third sentence';
const sentences = str.split('.');
sentences[0] // first sentence
sentences[1] // second sentence, etc

Answer 2

如果我没理解错的话，你应该可以

分期。获取字符串的长度。根据句子长度确定索引的位置。

考虑到您需要拆分“?, !”同样，您只需要遍历句子并将它们进一步扁平化。阿卡，再次分裂。

老实说，使用正则表达式和组可能更干净。

这是正则表达式版本

    const paragraph = "Dana's places, we're having people coming to us people wanna buy condos. They want to move quickly and we're just losing out on a lot of great places. Really what would you say this?"


    /**
     * Finds sentence by character index
     * @param index 
     * @param paragraph 
     */
    function findSentenceByCharacterIndex(index, paragraph) {

        const regex = /([^.!?]*[.!?])/gm

        const matches = paragraph.match(regex);

        let cursor = 0;

        let sentenceFound;

        for (const sentence of matches) {

            sentenceFound = sentence;

            cursor += sentence.length;

            if( cursor > index )
            {
                break;
            }
        }

        return sentenceFound;
    }


    const found = findSentenceByCharacterIndex(5, paragraph);

Answer 3

与其尝试使用 Array.split，不如对字符串进行一些传统字符的字符解析。因为我们知道要查找的索引是什么，所以我们可以简单地四处寻找句子的开头和结尾。

一个句子如何结束？通常使用 .、! 或 ? - 了解这一点后，我们可以测试这些字符并决定我们使用字符串的哪一部分应该切掉 return 回到程序。如果在我们选择的索引之前没有 sentence enders(a.e.?!.) 我们假设字符串的开头是当前句子的开头( 0) - 我们在我们选择的索引之后做同样的事情，除了我们分配 str.length 如果在索引之后没有句子结束符。

let str = "Dana's places, we're having people coming to us people wanna buy condos. They want to move quickly and we're just losing out on a lot of great places. Really what would you say this?";

let getSentence = (ind, str) => {
  let beg, end, flag, sentenceEnder = ["!", ".", "?"];
  Array.from(str).forEach((c, c_index) => {
  if(c_index < ind && sentenceEnder.includes(c)) {
   beg = c_index + 1;
  }
    if (flag) return;
    if (c_index >= ind && sentenceEnder.includes(c)) {
      end = c_index;
      flag = true;
    }
  });
  end = end || str.length;
  beg = beg || 0;
  return str.slice(beg, end);
}

console.log(getSentence(10, str));
console.log(getSentence(80, str));

给定一个索引位置，我如何拆分出该位置所在的句子？

Given an index position, how can I split out the sentence that that position lies in?

javascript

nlp

string-parsing