SQL VERTICA 运行总计 30/60/90 天

Question

嗨，我有两个 table 具有多对多关系

作为结果，我希望每条记录的得分为 table（因此 id_case 和 id_date）我希望看到从 scoring.id_date 到 scoring.id_date+30天，+60天等

这是我到目前为止想出来的，但它根本不起作用：

  with t as  (select id_case,id_date,amount 
                    from TableTransactions 
                     ) 


            SELECT id_case,f.id_date,
                   sum(case when exists (select * from t t where t.id_case=f.id_case and t.id_date between f.id_date and (to_char(date(cast( f.id_date as varchar(8))) + 360, 'YYYYMMDD'))::int ) then t.amount else 0 end )  as Days360

            from TableScoring f

Answer 1

我认为这是一个 join 条件聚合：

select s.id_case, s.id_date,
       sum(case when t.id_date >= s.id_date and t.id_date < s.id_date + interval '30 day'
                then t.amount else 0
           end) as amount_30,
       sum(case when t.id_date >= s.id_date and t.id_date < s.id_date + interval '60 day'
                then t.amount else 0
           end) as amount_60,
       sum(case when t.id_date >= s.id_date and t.id_date < s.id_date + interval '90 day'
                then t.amount else 0
           end) as amount_90
from scoring s join
     transactions t
     on t.id_case = s.id_case
group by s.id_case, s.id_date;

SQL VERTICA 运行总计 30/60/90 天

SQL VERTICA running sums 30/60/90 days

sql

database

vertica

SQL VERTICA 运行 总计 30/60/90 天

SQL VERTICA running sums 30/60/90 days

sql

database

vertica

SQL VERTICA 运行总计 30/60/90 天