Yii 第二个查询参数

Question

我使用 Yii 查询我的数据库

$query = Task::find()
        ->where([Task::tableName().'.parent_id' => 0]);
$query->leftJoin(TaskModel::tableName(), [TaskModel::tableName().'.task_id' => Task::tableName().'.id']);
$query->andWhere([TaskModel::tableName().'.format' => null]);
$rows = $query
        ->offset($pages->offset)
        ->limit($pages->limit)
        ->orderBy([
            Task::tableName().'.status' => SORT_DESC,
            Task::tableName().'.`estimated_date`=0' => SORT_ASC,
            Task::tableName().'.estimated_date' => SORT_ASC
        ])
        ->all();

但这不起作用，因为在 leftJoin 中，当我设置表之间的关系时，第二个参数设置字符串。

我查询的 rawSql：

SELECT `task`.* 
FROM `task` LEFT JOIN `task_model`
ON `task_model`.`task_id`='{{%task}}.id'
WHERE (`task`.`parent_id`=0) AND (`task_model`.`task_id` IS NULL)

Answer 1

在这种情况下你应该使用字符串：

$query->leftJoin(TaskModel::tableName(), TaskModel::tableName() . '.task_id = ' . Task::tableName() . '.id');

这种情况在documentation中明确提及：

Note that the array format of where() is designed to match columns to values instead of columns to columns, so the following would not work as expected: ['post.author_id' => 'user.id'], it would match the post.author_id column value against the string 'user.id'. It is recommended to use the string syntax here which is more suited for a join:
'post.author_id = user.id'

Yii 第二个查询参数

Yii second query parameter

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mysql

yii

yii2