Oracle 中的递归查询以查找 children 和兄弟姐妹
Recursive query in Oracle to find children and sibling
我正在努力进行分层 SQL 查询。我想要它的 children 和兄弟姐妹的 disp_order 的另外 2 列。
Children - 应该持有他们所有 disp_order 的 child 和他们的盛大 children 和到目前为止。
Sibling - 应该持有具有相同 parent.
的行的 disp_order
+------------+-----+-------------+--------+
| disp_order | lvl | description | parent |
+------------+-----+-------------+--------+
| 0 | 1 | A | |
| 1 | 2 | B | 0 |
| 2 | 3 | C | 1 |
| 3 | 4 | D | 2 |
| 4 | 5 | E | 3 |
| 5 | 2 | F | 0 |
| 6 | 3 | G | 5 |
| 7 | 3 | H | 5 |
| 8 | 3 | I | 5 |
| 9 | 4 | J | 8 |
| 10 | 5 | K | 9 |
+------------+-----+-------------+--------+
结果应该是什么:
+------------+-----+-------------+--------+------------------------+---------+
| disp_order | lvl | description | parent | children | sibling |
+------------+-----+-------------+--------+------------------------+---------+
| 0 | 1 | A | | 1,2,3,4,5,6,7,8,9,10 | |
| 1 | 2 | B | 0 | 2,3,4 | 5 |
| 2 | 3 | C | 1 | 3,4 | |
| 3 | 4 | D | 2 | 4 | |
| 4 | 5 | E | 3 | | |
| 5 | 2 | F | 0 | 6,7,8,9,10 | 1 |
| 6 | 3 | G | 5 | | 7,8 |
| 7 | 3 | H | 5 | | 6,8 |
| 8 | 3 | I | 5 | 9,10 | 6,7 |
| 9 | 4 | J | 8 | 10 | |
| 10 | 5 | K | 9 | | |
+------------+-----+-------------+--------+------------------------+---------+
这是我当前的查询:
SELECT t.*,
( SELECT MAX( disp_order )
FROM tbl_pattern p
WHERE p.lvl = t.lvl - 1
AND p.disp_order < t.disp_order ) AS parent
FROM tbl_pattern t
从 继续:
Oracle 11g R2 架构设置:
CREATE TABLE tbl_pattern ( order_no, code, disp_order, lvl, description ) AS
SELECT 'RM001-01', 1, 0, 1, 'HK140904-1A' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 1, 2, 'HK140904-1B' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 2, 3, 'HK140904-1B' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 3, 4, 'HK140904-1C' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 4, 5, 'HK140904-1D' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 5, 2, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 6, 3, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 7, 3, 'HK140904-1X' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 8, 4, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 9, 5, 'HK140904-1E' FROM DUAL;
查询 1:
WITH data ( order_no, code, disp_order, lvl, description, parent ) AS (
SELECT t.*,
( SELECT MAX( disp_order )
FROM tbl_pattern p
WHERE p.order_no = t.order_no
AND p.code = t.code
AND p.lvl = t.lvl - 1
AND p.disp_order < t.disp_order ) AS parent
FROM tbl_pattern t
)
SELECT d.*,
( SELECT LISTAGG( c.disp_order, ',' ) WITHIN GROUP ( ORDER BY c.disp_order )
FROM data c
START WITH c.parent = d.disp_order
AND c.order_no = d.order_no
AND c.code = d.code
CONNECT BY PRIOR c.disp_order = c.parent
AND PRIOR c.order_no = c.order_no
AND PRIOR c.code = c.code
) AS children,
( SELECT LISTAGG( c.disp_order, ',' ) WITHIN GROUP ( ORDER BY c.disp_order )
FROM data c
WHERE c.parent = d.parent
AND c.disp_order <> d.disp_order
AND c.order_no = d.order_no
AND c.code = d.code
) AS siblings
FROM data d
| ORDER_NO | CODE | DISP_ORDER | LVL | DESCRIPTION | PARENT | CHILDREN | SIBLINGS |
|----------|------|------------|-----|-------------|--------|-------------------|----------|
| RM001-01 | 1 | 0 | 1 | HK140904-1A | (null) | 1,2,3,4,5,6,7,8,9 | (null) |
| RM001-01 | 1 | 1 | 2 | HK140904-1B | 0 | 2,3,4 | 5 |
| RM001-01 | 1 | 2 | 3 | HK140904-1B | 1 | 3,4 | (null) |
| RM001-01 | 1 | 3 | 4 | HK140904-1C | 2 | 4 | (null) |
| RM001-01 | 1 | 4 | 5 | HK140904-1D | 3 | (null) | (null) |
| RM001-01 | 1 | 5 | 2 | HK140904-1E | 0 | 6,7,8,9 | 1 |
| RM001-01 | 1 | 6 | 3 | HK140904-1E | 5 | (null) | 7 |
| RM001-01 | 1 | 7 | 3 | HK140904-1X | 5 | 8,9 | 6 |
| RM001-01 | 1 | 8 | 4 | HK140904-1E | 7 | 9 | (null) |
| RM001-01 | 1 | 9 | 5 | HK140904-1E | 8 | (null) | (null) |
我正在努力进行分层 SQL 查询。我想要它的 children 和兄弟姐妹的 disp_order 的另外 2 列。
Children - 应该持有他们所有 disp_order 的 child 和他们的盛大 children 和到目前为止。
Sibling - 应该持有具有相同 parent.
的行的 disp_order+------------+-----+-------------+--------+
| disp_order | lvl | description | parent |
+------------+-----+-------------+--------+
| 0 | 1 | A | |
| 1 | 2 | B | 0 |
| 2 | 3 | C | 1 |
| 3 | 4 | D | 2 |
| 4 | 5 | E | 3 |
| 5 | 2 | F | 0 |
| 6 | 3 | G | 5 |
| 7 | 3 | H | 5 |
| 8 | 3 | I | 5 |
| 9 | 4 | J | 8 |
| 10 | 5 | K | 9 |
+------------+-----+-------------+--------+
结果应该是什么:
+------------+-----+-------------+--------+------------------------+---------+
| disp_order | lvl | description | parent | children | sibling |
+------------+-----+-------------+--------+------------------------+---------+
| 0 | 1 | A | | 1,2,3,4,5,6,7,8,9,10 | |
| 1 | 2 | B | 0 | 2,3,4 | 5 |
| 2 | 3 | C | 1 | 3,4 | |
| 3 | 4 | D | 2 | 4 | |
| 4 | 5 | E | 3 | | |
| 5 | 2 | F | 0 | 6,7,8,9,10 | 1 |
| 6 | 3 | G | 5 | | 7,8 |
| 7 | 3 | H | 5 | | 6,8 |
| 8 | 3 | I | 5 | 9,10 | 6,7 |
| 9 | 4 | J | 8 | 10 | |
| 10 | 5 | K | 9 | | |
+------------+-----+-------------+--------+------------------------+---------+
这是我当前的查询:
SELECT t.*,
( SELECT MAX( disp_order )
FROM tbl_pattern p
WHERE p.lvl = t.lvl - 1
AND p.disp_order < t.disp_order ) AS parent
FROM tbl_pattern t
从
Oracle 11g R2 架构设置:
CREATE TABLE tbl_pattern ( order_no, code, disp_order, lvl, description ) AS
SELECT 'RM001-01', 1, 0, 1, 'HK140904-1A' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 1, 2, 'HK140904-1B' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 2, 3, 'HK140904-1B' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 3, 4, 'HK140904-1C' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 4, 5, 'HK140904-1D' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 5, 2, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 6, 3, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 7, 3, 'HK140904-1X' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 8, 4, 'HK140904-1E' FROM DUAL UNION ALL
SELECT 'RM001-01', 1, 9, 5, 'HK140904-1E' FROM DUAL;
查询 1:
WITH data ( order_no, code, disp_order, lvl, description, parent ) AS (
SELECT t.*,
( SELECT MAX( disp_order )
FROM tbl_pattern p
WHERE p.order_no = t.order_no
AND p.code = t.code
AND p.lvl = t.lvl - 1
AND p.disp_order < t.disp_order ) AS parent
FROM tbl_pattern t
)
SELECT d.*,
( SELECT LISTAGG( c.disp_order, ',' ) WITHIN GROUP ( ORDER BY c.disp_order )
FROM data c
START WITH c.parent = d.disp_order
AND c.order_no = d.order_no
AND c.code = d.code
CONNECT BY PRIOR c.disp_order = c.parent
AND PRIOR c.order_no = c.order_no
AND PRIOR c.code = c.code
) AS children,
( SELECT LISTAGG( c.disp_order, ',' ) WITHIN GROUP ( ORDER BY c.disp_order )
FROM data c
WHERE c.parent = d.parent
AND c.disp_order <> d.disp_order
AND c.order_no = d.order_no
AND c.code = d.code
) AS siblings
FROM data d
| ORDER_NO | CODE | DISP_ORDER | LVL | DESCRIPTION | PARENT | CHILDREN | SIBLINGS |
|----------|------|------------|-----|-------------|--------|-------------------|----------|
| RM001-01 | 1 | 0 | 1 | HK140904-1A | (null) | 1,2,3,4,5,6,7,8,9 | (null) |
| RM001-01 | 1 | 1 | 2 | HK140904-1B | 0 | 2,3,4 | 5 |
| RM001-01 | 1 | 2 | 3 | HK140904-1B | 1 | 3,4 | (null) |
| RM001-01 | 1 | 3 | 4 | HK140904-1C | 2 | 4 | (null) |
| RM001-01 | 1 | 4 | 5 | HK140904-1D | 3 | (null) | (null) |
| RM001-01 | 1 | 5 | 2 | HK140904-1E | 0 | 6,7,8,9 | 1 |
| RM001-01 | 1 | 6 | 3 | HK140904-1E | 5 | (null) | 7 |
| RM001-01 | 1 | 7 | 3 | HK140904-1X | 5 | 8,9 | 6 |
| RM001-01 | 1 | 8 | 4 | HK140904-1E | 7 | 9 | (null) |
| RM001-01 | 1 | 9 | 5 | HK140904-1E | 8 | (null) | (null) |