更新挂起代码 -- Python MySQL Connector

Question

所以我正在尝试更新 table 并且出于某种原因，此代码决定在执行时冻结。

import mysql.connector

cnx = mysql.connector.connect(user='user', password='password',
                              host='y u so interested',
                              database='discord')

cursor = cnx.cursor()

print ("Start")

update = ("UPDATE admin_daily_playtime_crp1 "
        "SET DiscordName = %s "
        "WHERE SteamName = %s ")
values = ("true", "Modern Mo")
cursor.execute(update, values)
cnx.commit()

print ("done")

Table 设置： https://gyazo.com/dde9475d33056b26c04d564e3e8f7349

Answer 1

考虑更新您的 table 以包含其中每一列的正确数据类型。我更改了您的代码片段以包含组织功能。调用函数 discordName(Discord Name, Steam Name) 它应该更新信息。我在我自己的数据库上测试过，它运行良好。

import mysql.connector



def connection():
    connection = mysql.connector.connect(user='root', password='', host='',database='discord')

    return connection

def discordName(discordName, steamName):
    con = connection()
    cursor = con.cursor()
    print ("Start")
    update = "UPDATE `admin_daily_playtime_crp1` SET `DiscordName` = %s WHERE `SteamName` = %s"
    cursor.execute(update, (discordName, steamName))
    print (cursor.rowcount, "record(s) affected!")
    con.commit()

有问题就问吧！这是我使用 https://gyazo.com/58dfd93e68ab4d452c896918f8ac2c8a

的新 table 的图像

更新挂起代码 -- Python MySQL Connector

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python

mysql

freeze

mysql-connector

sql-update