在 Python 中将 Curses 矩形框扩展到终端的边缘

Question

我在使用 Python 在 Curses 中创建矩形时遇到了一些问题。

这是我的代码：

import curses
from curses.textpad import Textbox, rectangle

def draw_menu(stdscr):

    stdscr.clear()
    stdscr.refresh()

    while True:
        stdscr.refresh()


        writebox_uly = (int(stdscr.getbegyx()[0]))
        writebox_ulx = (int(stdscr.getbegyx()[1]))
        writebox_lry = (int(stdscr.getmaxyx()[0] * 0.7))
        writebox_lrx = (int(stdscr.getmaxyx()[1] - 1))

        rectangle(stdscr, writebox_uly, writebox_ulx, writebox_lry, writebox_lrx)

        editwin_uly = (int(stdscr.getmaxyx()[0] * 0.7 + 1))
        editwin_ulx = (int(stdscr.getbegyx()[1]))
        editwin_lry = (int(stdscr.getmaxyx()[0] - 1))
        editwin_lrx = (int(stdscr.getmaxyx()[1] - 2))

        rectangle(stdscr, editwin_uly, editwin_ulx, editwin_lry, editwin_lrx)

def main():
    curses.wrapper(draw_menu)

if __name__ == "__main__":
    main()

这将创建两个漂亮的矩形，如下图所示：

您可能会注意到下方框的右下角不是内嵌的。这是因为 editwin_lrx = (int(stdscr.getmaxyx()[1] - 2))

此行将右下 X 坐标（右下角）设置为终端的最大宽度减去 2

将其更改为 editwin_lrx = (int(stdscr.getmaxyx()[1] - 5)) 将使框更靠左。

因此，理论上，将其更改为 editwin_lrx = (int(stdscr.getmaxyx()[1] - 1)) 会将其稍微向右推。

但它不会崩溃。

Traceback (most recent call last):
  File "temp.py", line 32, in <module>
    main()
  File "temp.py", line 29, in main
    curses.wrapper(draw_menu)
  File "/usr/lib/python3.6/curses/__init__.py", line 94, in wrapper
    return func(stdscr, *args, **kwds)
  File "temp.py", line 26, in draw_menu
    rectangle(stdscr, editwin_uly, editwin_ulx, editwin_lry, editwin_lrx)
  File "/usr/lib/python3.6/curses/textpad.py", line 16, in rectangle
    win.addch(lry, lrx, curses.ACS_LRCORNER)
_curses.error: addch() returned ERR

是否可以将第二个框的右侧延伸到最边缘，使其与第一个框对齐？

Answer 1

您必须捕获异常并忽略它。 rectangle 函数如下所示：

def rectangle(win, uly, ulx, lry, lrx):                                         
    """Draw a rectangle with corners at the provided upper-left                 
    and lower-right coordinates.                                                
    """                                                                         
    win.vline(uly+1, ulx, curses.ACS_VLINE, lry - uly - 1)                      
    win.hline(uly, ulx+1, curses.ACS_HLINE, lrx - ulx - 1)                      
    win.hline(lry, ulx+1, curses.ACS_HLINE, lrx - ulx - 1)                      
    win.vline(uly+1, lrx, curses.ACS_VLINE, lry - uly - 1)                      
    win.addch(uly, ulx, curses.ACS_ULCORNER)                                    
    win.addch(uly, lrx, curses.ACS_URCORNER)                                    
    win.addch(lry, lrx, curses.ACS_LRCORNER)                                    
    win.addch(lry, ulx, curses.ACS_LLCORNER)

如 manual page 中所述，在写入低级时诅咒 returns 一个错误（rectangle 应该忽略）屏幕右上角：

At the bottom of the current scrolling region, and if scrollok is enabled, the scrolling region is scrolled up one line.

If scrollok is not enabled, writing a character at the lower right margin succeeds. However, an error is returned because it is not possible to wrap to a new line

在 Python 中将 Curses 矩形框扩展到终端的边缘

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