JPA：当 class 使用 EmbeddedId 时保持自我关系

Question

我有这个自我关系

    public class Estoria implements Serializable {

      @EmbeddedId 
      protected EstoriaPK estoriaPK; 

      @ManyToOne
      @JoinColumns({@JoinColumn(name = "id_estoria", referencedColumnName = "id", updatable = false, insertable = false, nullable = true)
                  ,@JoinColumn(name = "id_projeto" , referencedColumnName = "id_projeto" ,     insertable = false, updatable = false)})
      private Estoria subtask;

      @OneToMany(mappedBy = "subtask",cascade = CascadeType.ALL) 
      private Collection<Estoria> subtasks; 
    }

和我的 ID

    @Embeddable 
    public class EstoriaPK implements Serializable {

     @Basic(optional = false)
      @Column(name = "id", unique = true, nullable = false)
      private int id;
      @Basic(optional = false)
      @NotNull
      @Column(name = "id_projeto", unique = true, nullable = false)
      private int idProjeto;

      // GETTRs and SETTERs
    }

而且我尝试坚持使用级联

        public void persistSubtask(int idEstoria,Estoria subtask) {
        try {
            estoria = this.entityManager.createNamedQuery("Estoria.findById",Estoria.class)
                                .setParameter("id", idEstoria)
                                .getSingleResult();

            subtask.setEstoriaPK(new EstoriaPK(0,estoria.getProjeto().getId())); 
            subtask.setSubtask(estoria);
            this.entityManager.persist(subtask);  


        } catch (Exception e) {
            throw new NoPersistException("falha ao persistir subtask");
        } 
    }

这不起作用，因为我的外键没有持久化，是否有一些注释错误？

如果我尝试持久化一个集合因为它们的父引用不持久化而无法正常工作，是否还有其他注释问题需要我修复？

Answer 1

问题似乎是

insertable = false, updatable = false

JPA：当 class 使用 EmbeddedId 时保持自我关系

JPA: persist self relationship when class uses EmbeddedId

java

jpa