在 java 中掷两个骰子直到 dice1 大于 dice2 两次

Question

骰子的输出是随机的，我为此创建了一个函数。我想记录连续两次让骰子 1 大于骰子 2 需要多少 "attempts"。所以当它连续两次变大时，我希望它打印（"it took" + trials + "for d1 to be larger than d2 two times in a row"）。到目前为止我有这个但卡住了：

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

              int d1 = Dice();
              int d2 = Dice();
              int trials = 0;

              for (int i = 0; i < 100000; i++) {
               if (t1 > t2) {
               trials++;
               if (t1 > t2) {
                trials++ 
               }
              }
             }

            System.out.println(trials);
    } 
}

Answer 1

做这样的事情（将以下内容视为伪代码）：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            trials++;
        }
    }
    System.out.println(trials);
}

编辑：

要连续两次获得 dice1 值大于 dice2 值的尝试，可以执行以下操作：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            break;
        }else{
            trials++;
        }
    }
    System.out.println(trials);
}

Answer 2

我会选择

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {
  int trials = 0;
  int count = 0;

  while (count < 2) {
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      ++count;
    } else {
      count = 0;
    }

    ++trials;
  }

  println("It took " + trials + " trials for d1 to be larger than d2 " + count + " times in a row.")
}

Answer 3

欢迎来到 SO！这应该工作。查看评论，了解您做错的几件事和一些解释。

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

  // initialize variables to be updated in the loop
  int trials = 0;
  Boolean lastTimeD1WasGreater = false;

  for (int i = 0; i < 100000; i++) {
    // always increment the counter!
    trials++;

    // you had the wrong variable names here.
    // also they must be INSIDE the loop or else they would always come out the same
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      if (lastTimeD1WasGreater) {
        // if it was greater both last time and this time then we're done!
        System.out.println("it took " + trials + " trials.");
        break;
      } else {
        // otherwise set this variable so we can be on the lookout next time.
        lastTimeD1WasGreater = true;
      }
    } else {
      // d1 was not greater, so we'll start looking for a pair in the next loop.
      lastTimeD1WasGreater = false;
    }
  }
}

Answer 4

您可以在主函数中轻松完成此操作，除非需要使用外部函数来 return 随机。

public static void main(String[] args)
{
      int d1 = 0;
      int d2 = 0;
      int trials = 0;
      int d1bigger = 0;
      Random rand = new Random();

      while(d1bigger < 2)
      {
            d1 = rand.nextInt((6 - 1) + 1) + 1 ;
            d2 = rand.nextInt((6 - 1) + 1) + 1 ;
            if(d1 > d2)
            {
                d1bigger ++;
                trials++;
            }
            if(d2 > d1)
            {
                d1bigger = 0;
                trials++;
            }                
      }
      System.out.println("It took " + trials +  " trials for d1 to be larger than d2 two times in a row");
}

d1连续两次大于d2用了7次

示例输出

Answer 5

这是我想出的

import java.util.Random;

public class 主要{

public static int Dice() {
    return (int) (Math.random() * 6.0) + 1;
}

public static void main(String[] args) {
    Random rand = new Random();


    int trials = 0;
    int twoTimes = 0;

    do {
        int d1 = rand.nextInt(25) + 1;
        int d2 = rand.nextInt(25) + 1;
        trials++;
        if (d1 > d2) {
            twoTimes++;
            System.out.printf("%s time greater\nd1 was " + d1 + "\nd2 was " + d2 + "\n-------\n", twoTimes);
        }
    }

    while (twoTimes != 2);
    System.out.printf("\nIt took %s times", trials);

}

}

在 java 中掷两个骰子直到 dice1 大于 dice2 两次

Rolling two dices until dice1 is larger than dice2 two times in java

java

loops

dice